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**1. Homework Statement**

As we know, If a body is projected horizontally from a height h with velocity u and time taken by the body to reach the ground is T, then h = 0 + (1/2)gT2 (for vertical motion)

T = √2h/g

Why here 'ut' I mean t = 0, 'u (initial velocity should be zero but why "t = 0"? Could you explain, please

**2. Homework Equations**

**3. The Attempt at a Solution**

h = ut + (1/2)gT^2 where u = initial velocity, g = acceleration, t = initial time, T = finial time