Why there is no isotope of hydrogen with an atomic weight of four?

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SUMMARY

The discussion centers on the absence of a hydrogen isotope with an atomic weight of four, specifically H^4, which would consist of one proton and three neutrons. Participants highlight that such a configuration would likely be unstable due to internuclear forces and the principles of isospin. Tritium (H^3), which has one proton and two neutrons, is mentioned as a radioactive isotope that decays, suggesting that adding an additional neutron to create H^4 would not yield a stable nucleus. The conversation emphasizes the role of the Pauli Exclusion Principle and isospin in nuclear stability.

PREREQUISITES
  • Understanding of nuclear physics concepts, particularly isotopes and atomic structure.
  • Familiarity with isospin and its implications in nuclear interactions.
  • Knowledge of the Pauli Exclusion Principle and its effects on particle configurations.
  • Basic understanding of radioactive decay processes, specifically in isotopes like tritium.
NEXT STEPS
  • Research the stability of isotopes and the factors influencing nuclear configurations.
  • Explore the concept of isospin in greater detail, particularly in relation to nuclear forces.
  • Study the decay processes of radioactive isotopes, focusing on tritium and its decay products.
  • Investigate the implications of the Pauli Exclusion Principle in multi-nucleon systems.
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Students and professionals in nuclear physics, researchers exploring isotopic stability, and educators teaching atomic structure and nuclear interactions.

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Homework Statement





Homework Equations


why there is no isotope of hydrogen with an atomic weight of four?


The Attempt at a Solution


i find that such an isotope would have an isotopic spin state of 1/2 |2-1> + 3/2 |1 -1>
is there a reason for this state to not exist?
 
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Do you mean hydrogen with a nucleus of 1 proton and 3 neutrons?

Tritium is a radioactive isotope of hydrogen with 1 proton and 2 neutrons. It usually decays via
<br /> H^3 -&gt; (He^3)^+ + e^- + \nu^-<br />

Perhaps <br /> H^4<br /> would be unstable due to internuclear forces.

jsc
 
yes. I want to explain why a nucleus of 1 proton and 3 neutrons does not exist by using the isospin.
so i thought i should calculate the isospin of the combination n+n, then the combination p+n and then combine the results to find the isospin of the nucleus.
i assume that i sould find an unreasonable result to explain why it doesn't exist.
Any idea?
 
There are no restrictions, other than that supplied by the Pauli Principle, on isospins of any set of protons and neutrons. Why would there be?

Why would Nature allow Helium 4, but not Hydrogen 4?
Regards,
Reilly Atkinson
 
i did my research on the subject and you are wright reilly.
thanks!
 

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