Why's radial acceleration zero at north pole (1 Viewer)

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

84
0
a)Compute hte radial accleration of a point at the equator of the earth. b)repeat for the north pole of hte earth. Take the radius of the eartk to be 6370 km.

so for a) i got 9.9337 m/s square which is right
but for b) the answer is just zero
why?
 
You are at the "center" of rotation. You really are not moving anywhere are you? Just spinning...
 

lightgrav

Homework Helper
1,248
30
Whoa!

What Force could cause an acceleration as quick as 9.934 m/s^2 ?

I don't recall having to be tied down in Equador, to stay on the ground. (;->
 

Tide

Science Advisor
Homework Helper
3,078
0
lightgrav said:
Whoa!

What Force could cause an acceleration as quick as 9.934 m/s^2 ?

I don't recall having to be tied down in Equador, to stay on the ground. (;->
Yeah, but have you actually ever BEEN to the equator? ;)
 
a)Compute hte radial accleration of a point at the equator of the earth. b)repeat for the north pole of hte earth. Take the radius of the eartk to be 6370 km.

so for a) i got 9.9337 m/s square which is right
but for b) the answer is just zero
why?
Your part "a" isn't correct it says you need to find the acceleration not velocity, the velocity you find also incorrect.
 
hey.there's zero acceleration at poles because the R in the mrw^2 is approaching zero.or rather zero in this case.as it reaches the pole, the centripetal radius becomes zero, Fc=0 therefore, no acceleration.hope this helps.heh i'm new here.
 

The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top