Will Mixing CaCl2 and NaOH Solutions Form a Precipitate?

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SUMMARY

The combination of 100 mL of 0.10 mol/L CaCl2 solution and 50.0 mL of 0.070 mol/L NaOH solution results in the formation of calcium hydroxide, Ca(OH)2, which has a solubility product (Ksp) of 7.9 x 10^-6 at 25 degrees Celsius. To determine if a precipitate forms, the ion product must be calculated and compared to the Ksp. The ion product exceeds the Ksp, confirming that a precipitate of Ca(OH)2 will indeed form upon mixing these solutions.

PREREQUISITES
  • Understanding of solubility product constants (Ksp)
  • Knowledge of precipitation reactions in aqueous solutions
  • Familiarity with molarity calculations
  • Basic principles of ionic compounds and their solubility
NEXT STEPS
  • Calculate the ion product for the reaction between CaCl2 and NaOH
  • Research the solubility product constants for other common hydroxides
  • Study the principles of Le Chatelier's principle in relation to precipitation
  • Explore the effects of temperature on solubility and precipitation reactions
USEFUL FOR

Chemistry students, laboratory technicians, and anyone involved in analytical chemistry or studying precipitation reactions in aqueous solutions.

proskier
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Help please!

Here's the question I'm having problems with:

The solubility product of calcium hydroxide, Ca(OH)2, is 7.9 x 10^-6 at 25 degrees celsius. Will a precipitate form when 100mL of 0.10 mol/L of CaCl2 solution and 50.0 mL of 0.070 mol/L of NaOH solution are combined?


Do I need to find the solubility product for CaCl2 and NaOH before I can determine if a precipitate will form when they're added to Ca(OH)2. Any help will be greatful. I don't even know if I'm on the right track or not.

Thanks
 
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proskier said:
Help please!

Here's the question I'm having problems with:

The solubility product of calcium hydroxide, Ca(OH)2, is 7.9 x 10^-6 at 25 degrees celsius. Will a precipitate form when 100mL of 0.10 mol/L of CaCl2 solution and 50.0 mL of 0.070 mol/L of NaOH solution are combined?


Do I need to find the solubility product for CaCl2 and NaOH before I can determine if a precipitate will form when they're added to Ca(OH)2. Any help will be greatful. I don't even know if I'm on the right track or not.

Thanks


Assume that CaCl2 and NaOH are both soluble at the specified concentrations.
 

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