Will Reflected Light Produce a Bright Spot with Thin Film Interference?

Click For Summary
SUMMARY

The discussion centers on the phenomenon of thin film interference in light reflected from two glass sheets with an air gap. Given a wavelength of 580 nm and an air gap thickness of 870 nm, the calculated path difference results in a total phase difference of 7π, indicating destructive interference. This confirms that the reflected light will produce a dark spot rather than a bright one. The key takeaway is that while both arguments regarding path difference and phase change are valid, the phase difference ultimately determines the interference outcome.

PREREQUISITES
  • Understanding of thin film interference principles
  • Familiarity with wave optics and phase changes upon reflection
  • Knowledge of the wavelength of light and its impact on interference patterns
  • Ability to apply the equation 2t = mλ for path difference calculations
NEXT STEPS
  • Study the principles of thin film interference in more detail
  • Learn about phase changes upon reflection from different media
  • Explore the mathematical derivation of interference conditions
  • Investigate applications of thin film interference in optical coatings
USEFUL FOR

Students and educators in physics, particularly those focused on optics, as well as professionals working in fields involving optical engineering and materials science.

NATURE.M
Messages
298
Reaction score
0

Homework Statement



Light strikes two plane sheets of glass with a thin air space between them as shown. If the light has a wavelength of 580 nm and the air space between the glass has a thickness of 870 nm, predict whether the reflected light as demonstrated by rays A and B will cancel or produce a bright spot.

Homework Equations



2t=mλ, m=1,2,3...


The Attempt at a Solution



So using the above equation, and substituting the values in the question, I obtain, m=3. So the path difference is 3λ (extra distance ray B travels)
Then since the second ray (ray B) is reflected from a denser medium (glass), it is in phase reversal or λ/2 out of phase. So, then the total path difference is 3.5 λ. Since its a half-integral multiple it implies the rays will cancel-produce a dark spot.
Is this logic correct?

I've been told this is the correct answer, but initially I would have said that the path difference is 3λ, since the rays are already out of phase-and destructive interference would occur-producing a dark spot. Then the whole integral number of wavelengths (3λ in this case), wouldn't change the status of the system, so the rays will cancel. But this is supposedly wrong, with the first answer being correct.
Can someone please clarify why this is true.
 
Physics news on Phys.org
Both arguments are correct, integer number of wavelengths in the path difference do not count.

ehild
 
ehild said:
Both arguments are correct, integer number of wavelengths in the path difference do not count.

ehild

Would you advise its better to use the first argument, or does it really not matter?
 
I think the firs argument is better to use. But I prefer argument referring to phase difference. If the phase diference between two waves is odd number of pi, the interference is destructive, if it is even number of pi, it is constructive.

Travelling across λ distance changes the phase by 2pi. Reflecting from a denser medium changes the phase by pi.
One ray reflects from the front surface of the air gap with no phase change. The other ray traverses the air gap (1.5 λ), changing the phase by 3 pi, reflects from a denser medium, that changes the phase by pi, then traverses the gap again, so the net phase difference between the waves is 7pi. Odd number of pi, so the waves interfere destructively.


ehild
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
913
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
4K
Replies
7
Views
6K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K