- #1

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[tex] (p-1)!=-1mod(p) [/tex]

how could you derive the formulae for [tex] pi(x) [/tex]?..this should be impossible as you can,t solve the congruence exactly a proposed method would be to find the roots of:

[tex]f(x)=[\gamma(x)+1/x]-(\gamma(x)+1)/x [/tex]

that precisely x=p for every prime and intege...