Window area question, express as function of Area

Click For Summary

Homework Help Overview

The problem involves a window shaped as a rectangle with an equilateral triangle on top, where the perimeter is given as 15 feet. Participants are tasked with expressing the area as a function of the length of one side of the equilateral triangle.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • One participant attempts to express the area using the perimeter and the dimensions of the shapes involved, while another questions the perimeter equation and suggests an alternative interpretation involving the rectangle's dimensions. There is also discussion about the correct interpretation of the term "surmounted" and its implications for the shape configuration.

Discussion Status

The discussion is active with various interpretations being explored. Some participants provide guidance on the area calculations, while others clarify misunderstandings regarding the geometric arrangement of the window components. There is no explicit consensus on the approach to take.

Contextual Notes

Participants are navigating potential misunderstandings about the geometric configuration and the implications of the perimeter constraint. There is also a mention of the domain for the variable related to the triangle's side length.

lovemake1
Messages
147
Reaction score
1

Homework Statement



A window has the shape of a rectangle surmounted by an equilateral triangle. Given that the perimeter of the window is 15 feet, express the area as a function of the length of one side of the equilateral triangle.

Homework Equations



Area of an equaliteral triangle : x^2(sqrt (3)) / 4

Surface area of the window : 3x + 2y = 15
reduced to : y = (15 - 3x) / 2

Volume of the window: X^2(sqrt(3)) / 4 + xy

The Attempt at a Solution



y = (15 - 3x) / 2 has domain of 0 <= x <= 5

i subbed in y into the vlume of the window,
x^2(sqrt(3)) / 4 + x(15-3x)/2

and after factoring out the x, I got [x(x*Sqrt(3) - 6x + 30)] / 4
and with new domain 0 < x < 5.


Am i takin the right approach? am i suppose to leave the sqrt where it is right now?
please help
 
Physics news on Phys.org
Wouldn't the perimeter be 2x+2y=15? Then the area of the window is given by A=xy, but you know that x+y=7.5, then...
 
hunt_mat said:
Wouldn't the perimeter be 2x+2y=15? Then the area of the window is given by A=xy, but you know that x+y=7.5, then...

No, you're missing the equilateral triangle.

Lovemake1 yes that's perfect.
 
No, it says the perimeter of the 15, if the triangle fits snugly into the rectangle and the sides of the triangle is L, the one side is length L and the other side is given by [tex]L\sqrt{3}/2[/tex], so the area is given by [tex]L^{2}\sqrt{3}/2[/tex].
 
Surmounted means to sit on top of, not to sit snugly into.

And by the way, for an equilateral triangle, if one side is length L then the area is [tex]\frac{\sqrt{3}}{4}L^2[/tex]
 
Ah! I read surrounded.
 
hunt_mat said:
Ah! I read surrounded.

That would make for a weird question :-p
 
Not quite, it would mean that you could get a number for the area by using the perimeter.

Mat
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
5K
  • · Replies 23 ·
Replies
23
Views
4K
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
25K