With New Problem due Wednsday

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Homework Help Overview

The discussion revolves around finding a continuous, non-linear function f(x) that satisfies the equation f(x+1) = f(x) + 1. The original poster mentions that they need to create an example of such a function, as a step function previously discussed in class is not allowed.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore various function forms, questioning the definition of "unbroken" and clarifying that it refers to continuity. There is discussion about integer values and the implications of the functional equation on those values. Some participants suggest specific functions while others express doubt about the existence of a suitable function.

Discussion Status

The conversation is ongoing, with participants providing insights and questioning the requirements of the problem. Some suggestions have been made, but there is no consensus on a viable function yet. The original poster is encouraged to clarify the professor's expectations further.

Contextual Notes

Participants note constraints such as the prohibition of using trigonometric functions and the need for the function to be non-linear and continuous. There is uncertainty about the professor's exact requirements and the feasibility of finding such a function.

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Please Help With New Problem...due Wednsday!

The question is the following..

For all x f(x+1) = f(x)+1
a. f(x) has to be unbroken
b. f(x) is non-linear

I just have to come up with ANY example of f(x) for that to be true. So basically come up with any function which is unbroken and is not linear so that f(x+1) = f(x)+1 is true.

One example that he showed us in class was the step function, but he said we can't use that..so we have to make 1 up...can someone please HELP ME?
I though i had it with f(x) = |x^2| , but i am not sure..

f(x^2 + 1) = f(x^2) + 1??
 
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Do you mean f(x)=x^2? Because f(x^2) is not a "function", it's just what value to plug into some function 'f'. You need to find some f(x)="expression" such that f(x+1) = f(x)+1. So your idea, f(x^2), does not answer the question at hand. (And neither does f(x)=x^2.)

Now, I'm unclear what is meant by "unbroken". Do you mean continuous?
 
yes continuous and it has to be a NON-LINEAR function..and it has to follow the rule:

f(x+1) = f(x) + 1
 
anyone ...
 
Have you given any thought to what your f must be for x an integer?
f(1) can be any number, of course, but then f(2)= f(1+1)= f(1)+ 1. f(3)= f(2+1)= f(1)+ 1+ 1= f(1)+ 2, f(4)= f(3+1)= f(3)+ 1= f(1)+2+1= f(1)+ 3. It's easy to see (or prove by induction) that as long as n is an integer, f(n)= f(1)+ n-1. The LINEAR function f(x)= C+ x-1 for C any constant would work fine but your example must not be a linear. I thought about using the "floor" function but that would not be continuous.

I doubt that there is a continuous, non-linear, function satisfying that!
 
HallsofIvy said:
Have you given any thought to what your f must be for x an integer?
f(1) can be any number, of course, but then f(2)= f(1+1)= f(1)+ 1. f(3)= f(2+1)= f(1)+ 1+ 1= f(1)+ 2, f(4)= f(3+1)= f(3)+ 1= f(1)+2+1= f(1)+ 3. It's easy to see (or prove by induction) that as long as n is an integer, f(n)= f(1)+ n-1. The LINEAR function f(x)= C+ x-1 for C any constant would work fine but your example must not be a linear. I thought about using the "floor" function but that would not be continuous.

I doubt that there is a continuous, non-linear, function satisfying that!


My professor said that there are a lot of such functions...
 
[tex]n*cos 2 \pi n[/tex]

Would work for integer values. Maybe you heard him wrong and he wants something simple like this.
 
BlackWyvern said:
[tex]n*cos 2 \pi n[/tex]

Would work for integer values. Maybe you heard him wrong and he wants something simple like this.


I can't use any TRIGONOMETRY since we still didnt go over it in class, he wants a regular function.
 
It's going to be quite the task to find a non-linear, non-periodic, continuous function satisfying [tex]f(x+1) = f(x)+1[/tex]. You need to find more details about what this "professor" of yours is looking for, or at least make sure what you're telling us is accurate.

Other than that tidbit, good luck on finding this needle in a haystack.
 

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