With which speech goes the Mass through the Equilibrium?

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SUMMARY

The discussion revolves around calculating the speed of a mass at equilibrium in a thermodynamic context. The relevant equations include kinetic energy (Ekin = 1/2*m*v²), potential energy (Epot = m*g*h), and elastic energy (Es = 1/2*D*s²). The total energy at the highest point is approximately 6.573 Nm, derived from a mass of 1 kg at a height of 0.67 m. The problem was ultimately resolved by applying the given data directly into the equations, confirming the solution's validity.

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wiegetz
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Homework Statement


With which speed goes the Mass through the Equilibrium?

Homework Equations


Es = 1/2*D*s2
Ekin = 1/2*m*v2
Epot = m*g*h

Energy in the zero point = below/ under

highest Point: Epot = 1kg * 9,81N/kg*0.67m
≈ 6.573Nm

Equilibrium : Ekin, Epot, Es

Lowest Point: Es= 0 Ekin = 0, Epot = 0

The Attempt at a Solution


I have no Idea what I have to do. I found out that the total Energy needs to be approx. 6,573Nm of the system.
 
Last edited:
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Your problem statement makes no sense.

What speech? What equilibrium?
 
Sorry, I ment speed, not speech. The question is asked on a different language, so I tried to translate it. According to google, the correct meaning should be "
Thermodynamic equilibrium

"
 
wiegetz said:
Sorry, I ment speed, not speech. The question is asked on a different language, so I tried to translate it. According to google, the correct meaning should be "
Thermodynamic equilibrium

"
OK, things are a little clearer now. But what about the particulars of this problem? What does 0.67 m have to do with anything?
 
I solved this problem. I needed to insert the given data simply into the formula, I thought that this attempt would be too simple. Can be marked as solved!
 

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