WJEC GCSE Physics 2 Higher Tier Q5(c)(ii) Help

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SUMMARY

The discussion focuses on WJEC GCSE Physics 2 Higher Tier Question 5(c)(ii) from January 2014, which asks why a barium nucleus, released with the same kinetic energy as a neutron, has a velocity that is one twelfth (1/12) that of the neutron. The key conclusion is that the greater mass of the barium nucleus results in a significantly lower velocity when kinetic energy is held constant, as described by the equation KE = (1/2) mv². Participants emphasize the importance of understanding the mass-velocity relationship in this context.

PREREQUISITES
  • Understanding of kinetic energy (KE) and its formula KE = (1/2) mv²
  • Basic knowledge of nuclear physics, specifically the mass of barium compared to a neutron
  • Familiarity with the concept of velocity and its dependence on mass
  • Ability to set up proportions for comparative calculations
NEXT STEPS
  • Research the mass of barium compared to a neutron for better context
  • Study the implications of mass on velocity in kinetic energy equations
  • Explore additional examples of mass-velocity relationships in particle physics
  • Practice solving problems involving kinetic energy and mass ratios
USEFUL FOR

Students preparing for the WJEC GCSE Physics exam, educators teaching physics concepts, and anyone interested in understanding the principles of kinetic energy and mass in nuclear physics.

Tomos
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Homework Statement


Question 5 (c) (ii) from the paper physics 2 higher tier January 2014 by wjec. There is no mark scheme at the moment of the paper and I do not understand the question. The paper is at the bottom of "papers" at http://www.wjec.co.uk/qualifications/qualification-resources.html?pastpaper=true&subject=Physics&level=gcse and the question is " if a barium nucleus is released with the same kinetic energy as a neutron, explain why the size of its velocity would only be one twelfth (1/12) of the velocity of a neutron". Please help!

Homework Equations


N/A

The Attempt at a Solution


Barium has a greater mass than a neutron?
 
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KE in this case is given by ##\frac{1}{2} mv^2## . You're close when you think about the difference in masses. What is their ratio? How does ##m## relate to ##v##? Think about it.
 
PWiz said:
KE in this case is given by ##\frac{1}{2} mv^2## . You're close when you think about the difference in masses. What is their ratio? How does ##m## relate to ##v##? Think about it.
Okay thanks!
 
With a greater mass and an equivalent kinetic energy, the velocity of the barium nucleus will be much small considering the mass is so much greater than that of the neutron. Ke=(1/2) mv^2 therefore if you set up a proportion you could calculate the velocity of the neutron compared to the barium.
 

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