WJEC GCSE Physics 2 Higher Tier Q5(c)(ii) Help

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Homework Help Overview

The discussion revolves around a question from the WJEC GCSE Physics exam regarding the relationship between mass and velocity in the context of kinetic energy. The original poster seeks clarification on why a barium nucleus, released with the same kinetic energy as a neutron, would have a velocity only one twelfth of that of the neutron.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the implications of mass on velocity when kinetic energy is held constant. There are inquiries about the ratio of the masses of the barium nucleus and the neutron, and how this affects their respective velocities.

Discussion Status

Some participants have offered insights into the relationship between mass and velocity, referencing the kinetic energy formula. There is an ongoing exploration of the concepts involved, with no explicit consensus reached yet.

Contextual Notes

The original poster notes the absence of a mark scheme for the question, which may contribute to the uncertainty in understanding the problem.

Tomos
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Homework Statement


Question 5 (c) (ii) from the paper physics 2 higher tier January 2014 by wjec. There is no mark scheme at the moment of the paper and I do not understand the question. The paper is at the bottom of "papers" at http://www.wjec.co.uk/qualifications/qualification-resources.html?pastpaper=true&subject=Physics&level=gcse and the question is " if a barium nucleus is released with the same kinetic energy as a neutron, explain why the size of its velocity would only be one twelfth (1/12) of the velocity of a neutron". Please help!

Homework Equations


N/A

The Attempt at a Solution


Barium has a greater mass than a neutron?
 
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KE in this case is given by ##\frac{1}{2} mv^2## . You're close when you think about the difference in masses. What is their ratio? How does ##m## relate to ##v##? Think about it.
 
PWiz said:
KE in this case is given by ##\frac{1}{2} mv^2## . You're close when you think about the difference in masses. What is their ratio? How does ##m## relate to ##v##? Think about it.
Okay thanks!
 
With a greater mass and an equivalent kinetic energy, the velocity of the barium nucleus will be much small considering the mass is so much greater than that of the neutron. Ke=(1/2) mv^2 therefore if you set up a proportion you could calculate the velocity of the neutron compared to the barium.
 

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