Word problem - Application of linear equations

Click For Summary
SUMMARY

The discussion centers on solving a linear equation problem involving student enrollment in English courses based on an aptitude exam. The total number of freshmen is 1240, with more students in English Fundamentals than in English Composition. The correct equations derived from the problem are: P + F = 1240 and P + 30 = 1210 - P. Solving these equations reveals that 605 students are enrolled in English Composition and 635 in English Fundamentals, confirming the solution's accuracy.

PREREQUISITES
  • Understanding of linear equations and systems of equations
  • Basic algebraic manipulation skills
  • Familiarity with word problems in mathematics
  • Knowledge of variables and their representation in equations
NEXT STEPS
  • Study systems of linear equations and their applications
  • Practice solving word problems involving linear equations
  • Explore algebraic techniques for manipulating equations
  • Learn about real-world applications of linear equations in various fields
USEFUL FOR

Students, educators, and anyone interested in mastering linear equations and their applications in problem-solving scenarios.

paulmdrdo1
Messages
382
Reaction score
0
Every freshman student at a particular college is required to take an english aptitude exam. A student who passes the examination enrolls in english composition, and a student who fails the test must enroll in english fundamentals. In a freshman class of 1240 students there are more students enrolled in english fundamentals than in english composition. However, if 30 more students had passed the test, each course would have the same enrollment. how many students are taking each course?

My solution

let $x=$number of students who passed

$1240-x =$ number of students who failed

$x+30=1240-x$

$2x=1240-30$
$2x=1210$
$x=605$

605 students are taking English Composition
635 students are taking English fundamentals

is my solution correct?

thanks!
 
Mathematics news on Phys.org
I would let $P$ be the number who passed and $F$ be the number who failed. We are given in the problem:

$$P+F=1240$$

$$P+30=F-30$$

Note that if we add 30 to those that passed, then we have to subtract 30 from those that failed. So solve this system...what do you find?
 
paulmdrdo said:
Every freshman student at a particular college is required to take an english aptitude exam. A student who passes the examination enrolls in english composition, and a student who fails the test must enroll in english fundamentals. In a freshman class of 1240 students there are more students enrolled in english fundamentals than in english composition. However, if 30 more students had passed the test, each course would have the same enrollment. how many students are taking each course?

My solution

let $x=$number of students who passed

$1240-x =$ number of students who failed

$x+30=1240-x$
This is incorrect. "If 30 more students had passed the test" then, yes, the number of students who passed and so must take one course is x+ 30 but then the number who failed, and must take the other course would be 30 less: 1240- (x+ 30)= 1210- x.

The equation you want to solve is x+ 30= 1210- x.
$2x=1240-30$
$2x=1210$
$x=605$

605 students are taking English Composition
635 students are taking English fundamentals

is my solution correct?

thanks!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 44 ·
2
Replies
44
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
3K
  • · Replies 10 ·
Replies
10
Views
834
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
5K