Word problem : Finding the time in which workers can do a job .

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SUMMARY

The discussion focuses on solving a work problem involving five workers (W1, W2, W3, W4, and W5) and their combined work rates. The workers' rates are expressed as equations based on their collaborative times: W1, W2, W3 together in 7.5 hours; W1, W3, W5 in 5 hours; W1, W3, W4 in 6 hours; and W2, W4, W5 in 5 hours. The key conclusion is that the total time for all five workers to complete the job can be determined without solving for individual work rates, as W1 and W3 always work together, effectively reducing the number of unknowns.

PREREQUISITES
  • Understanding of work rate equations
  • Familiarity with algebraic manipulation of equations
  • Knowledge of reciprocal relationships in rates
  • Ability to interpret collaborative work scenarios
NEXT STEPS
  • Study the concept of combined work rates in algebra
  • Learn how to derive equations from collaborative work scenarios
  • Explore the implications of reciprocal rates in problem-solving
  • Practice similar work problems involving multiple workers and their rates
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Students, educators, and anyone interested in solving work-related mathematical problems, particularly those involving multiple contributors and their combined efficiencies.

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Homework Statement

Each one of the five workers W1, W2, W3, W4 and W5 can do a certain job.
W1, W2, W3 together can do it in 7.5 hours.
W1, W3, W5 together can do it in 5 hours.
W1, W3, W4 together can do it in 6 hours.
W2, W4, W5 together can do it in 5 hours.
Find the time in which all five together can complete the job.

Homework Equations



-

The Attempt at a Solution



Can I convert these conditions into equations like this - 1/w1 + 1/w2 + 1/w3 = 1/7.5 ??
Please help !
 
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Yes, that's exactly right. When people work together, their rates add. If W1 can do a job in w1 hours, he/she works at a rate of 1/w1 "job per hour".
So
"Each one of the five workers W1, W2, W3, W4 and W5 can do a certain job.
W1, W2, W3 together can do it in 7.5 hours." 1/w1+ 1/w2+ 1/w3= 1/7.5
"W1, W3, W5 together can do it in 5 hours." 1/w1+ 1/w3+ 1/w5= 1/5
"W1, W3, W4 together can do it in 6 hours." 1/w1+ 1/w3+ 1/w4= 1/6
"W2, W4, W5 together can do it in 5 hours." 1/w1+ 1/w4+ 1/w5= 1/5

Since you have only four equations in five unknowns, you cannot solve for the five values separately. Fortunately, the problem does not ask you to. It asks for 1/(w1+w2+ w3+ w4+ w5).
 
HallsofIvy said:
Yes, that's exactly right. When people work together, their rates add. If W1 can do a job in w1 hours, he/she works at a rate of 1/w1 "job per hour".
So
"Each one of the five workers W1, W2, W3, W4 and W5 can do a certain job.
W1, W2, W3 together can do it in 7.5 hours." 1/w1+ 1/w2+ 1/w3= 1/7.5
"W1, W3, W5 together can do it in 5 hours." 1/w1+ 1/w3+ 1/w5= 1/5
"W1, W3, W4 together can do it in 6 hours." 1/w1+ 1/w3+ 1/w4= 1/6
"W2, W4, W5 together can do it in 5 hours." 1/w2+ 1/w4+ 1/w5= 1/5

Since you have only four equations in five unknowns, you cannot solve for the five values separately. Fortunately, the problem does not ask you to. It asks for 1/(w1+w2+ w3+ w4+ w5).
Does it ask for 1/(w1+w2+ w3+ w4+ w5) or 1/w1+1/w2+1/w3+1/w4+1/w5 ?
 
Last edited:
Guys please help ! I'm not able to solve it.
 
agoogler said:
Does it ask for 1/(w1+w2+ w3+ w4+ w5) or 1/w1+1/w2+1/w3+1/w4+1/w5 ?
You're right, almost. Halls confused himself at the final step. You need 1/(1/w1+1/w2+1/w3+1/w4+1/w5).
It would be easier to think about working in terms of rates, r1..r5, rather than these inverted rates. But the equations are essentially the same: r1+r2+r3 = 1/7.5 etc. All working together, the total rate is r1+r2+r3+r4+r5. How do you turn that into the time they'll take?
Btw, there's something a bit special about the provided information which allows you to get the answer without finding all of r1 to r5. Can you see what it is?
 
haruspex said:
You're right, almost. Halls confused himself at the final step. You need 1/(1/w1+1/w2+1/w3+1/w4+1/w5).
It would be easier to think about working in terms of rates, r1..r5, rather than these inverted rates. But the equations are essentially the same: r1+r2+r3 = 1/7.5 etc. All working together, the total rate is r1+r2+r3+r4+r5. How do you turn that into the time they'll take?
Btw, there's something a bit special about the provided information which allows you to get the answer without finding all of r1 to r5. Can you see what it is?
The reciprocal of the total rate should be the time required . Um , since the first condition says r1+r2+r3=1/7.5 , I think I only need to find r4 and r5 then add it to that. Right ?
 
haruspex said:
You're right, almost. Halls confused himself at the final step.
I do that a lot!

You need 1/(1/w1+1/w2+1/w3+1/w4+1/w5).
It would be easier to think about working in terms of rates, r1..r5, rather than these inverted rates. But the equations are essentially the same: r1+r2+r3 = 1/7.5 etc. All working together, the total rate is r1+r2+r3+r4+r5. How do you turn that into the time they'll take?
Btw, there's something a bit special about the provided information which allows you to get the answer without finding all of r1 to r5. Can you see what it is?
 
agoogler said:
The reciprocal of the total rate should be the time required . Um , since the first condition says r1+r2+r3=1/7.5 , I think I only need to find r4 and r5 then add it to that. Right ?
Yes. (The special fact about the given data is that W1 and W3 always occur together, so as far as the sum of all five is concerned they constitute only one unknown.)
 
haruspex said:
Yes. (The special fact about the given data is that W1 and W3 always occur together, so as far as the sum of all five is concerned they constitute only one unknown.)
So I just tried to solve it and got the answer 10/3 , Am I right?
 
  • #10
agoogler said:
So I just tried to solve it and got the answer 10/3 , Am I right?

Yes. Fwiw, the easiest way is to take all the equations like r1+r2+r3=1/7.5, add them up, and add the last one (r2, r4, r5) in again. On the LHS you then have 3(r1+r2+r3+r4+r5).
 
  • #11
haruspex said:
Yes. Fwiw, the easiest way is to take all the equations like r1+r2+r3=1/7.5, add them up, and add the last one (r2, r4, r5) in again. On the LHS you then have 3(r1+r2+r3+r4+r5).
LOL , I didn't notice that. Thanks !
 

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