Bilinear Transformation problem

  • Thread starter Thread starter RJLiberator
  • Start date Start date
  • Tags Tags
    Transformation
Click For Summary
SUMMARY

The bilinear transformation that maps the points z1=infinity, z2=i, z3=0 to w1=0, w2=i, w3=infinity is given by the equation w=-1/z. The transformation is derived by setting the denominator to zero, which leads to the conclusion that d must equal 0. Further analysis shows that a must also equal 0, simplifying the equation to b/cz. The constants b and c can be any non-zero values that maintain the ratio, confirming that specific values like c=1 and b=-1 are not necessary for the transformation's validity.

PREREQUISITES
  • Understanding of bilinear transformations
  • Familiarity with complex numbers and their mappings
  • Knowledge of limits in calculus
  • Basic algebraic manipulation of equations
NEXT STEPS
  • Study the properties of bilinear transformations in complex analysis
  • Learn about the significance of mapping points in the complex plane
  • Explore the concept of limits and their applications in transformations
  • Investigate the implications of constant factors in mathematical transformations
USEFUL FOR

Students studying complex analysis, mathematicians interested in transformations, and educators teaching advanced algebra or calculus concepts.

RJLiberator
Gold Member
Messages
1,094
Reaction score
63

Homework Statement


Find the bilinear transformation that maps the points z1=infinity, z2=i, z3=0 to the points w1=0, w2=i, w3=infinity.

Homework Equations


w=(az+b)/(cz+d)

The answer is -1/z

The Attempt at a Solution



We have:
infinity --> 0
i --> i
0 --> infinity

Since 0 goes to infinity, it means the denominator "is 0", so therefore d must be 0 in our relevant equation right off the bat.

If we take the limit as z--> infinity, we are supposed to get w=0, so 0=a/c in the limit and we see that a=0.

So now we are left with b/cz
and i-->

i=b/(ci) and we see that -c=b

But how do I prove here that c=1, and b=-1 instead of something else?

thanks.
 
Physics news on Phys.org
RJLiberator said:
But how do I prove here that c=1, and b=-1 instead of something else?
This is irrelevant. If you take c = 2 and b = -2, you end up with the same transformation (i.e., the constants are only well defined up to an overall multiplicative factor).
 
Hm. Excellent, so what you are saying is it does not need to be proved since it's irrelevant.
It may as well be c=100, and b=-100 and then w'ed have
-100/(100z) which reduces to -1/z

Thanks.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K