High School Work and energy: conceptual doubt

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SUMMARY

The discussion centers on the concepts of work and energy in the context of a block being moved on a rough surface and lifted against gravity. The work done by the user is calculated as ##W_1=\mu mg d## for horizontal movement and ##W_1=mgh## for vertical movement, while the work done by friction and gravity is negative. The user questions the increase in potential energy of the block when the energy transferred appears to remain constant. The resolution lies in understanding that potential energy refers to the entire system, including the Earth and the block, rather than just the block itself.

PREREQUISITES
  • Understanding of classical mechanics principles, specifically work and energy.
  • Familiarity with gravitational potential energy and its implications.
  • Knowledge of frictional forces and their impact on energy transfer.
  • Ability to interpret and manipulate equations related to work and energy.
NEXT STEPS
  • Study the concept of gravitational potential energy in detail, focusing on its role in energy conservation.
  • Learn about the work-energy theorem and its applications in various physical scenarios.
  • Explore the implications of friction on energy transfer and system dynamics.
  • Read the Feynman Lectures on Physics, specifically the section on work and energy, for deeper insights.
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Students of physics, educators explaining work and energy concepts, and anyone interested in the principles of classical mechanics and energy conservation.

Lalit Tolani
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Suppose I am sliding a block very slowly on a rough surface. If the block has traveled ##d## distance then work done by me is ##W_1=\mu mg d## and that by friction is ##W_2=-\mu mg d##.

Now the energy transferred from me to block is ##\mu mgd## and that taken by friction from block is ##\mu mgd ##, The net energy of block remains same but the energy taken by friction evolves as heat and that is equal to my chemical energy consumed, so total energy of ##block + me## system remains constant.

Now If I pull a block of mass ##m## slowly towards up to a height ##h##, then work done by me is ##W_1=mgh## (assuming ##h## is much less than radius of earth) and that by gravity is ##W_2=-mgh##. Therefore ##mgh## goes from me to block and ##mgh## from block to earth, So here also energy of block doesn't change, then why do we say that potential energy of block increases.

I know I am lacking something here, as the total energy of the system would not be conserved if the block's energy doesn't change and my energy decreases.

Please help me in understanding where I am wrong.
 
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Lalit Tolani said:
So here also energy of block doesn't change, then why do we say that potential energy of block increases.
The kinetic energy of the block doesn't change, since the net work done on it is zero. Note that there are two ways to talk about the work done by gravity in these sorts of situations: You can explicitly treat gravity as a force, calculating the work it does on the object. Or you can treat it by using gravitational potential energy. But what you cannot do is use both -- that would be counting gravity twice, in effect.
 
Lalit Tolani said:
So here also energy of block doesn't change, then why do we say that potential energy of block increases.
When you get a chance, try reading https://www.feynmanlectures.caltech.edu/I_04.html

Some of the problem here is that the English language is being used imprecisely; strictly speaking we don't have "potential eergy of the block", we have the potential energy of the entire system consisting of the Earth and the block.

Imagine that we've enclosed the whole shebang (earth, block, you, lifting mechanism) in a huge box. Now the total amount of energy inside the box will be conserved as long as we count an increase in potential energy as the block and the Earth are pulled apart.
 
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