Work Done by Force in First 4 Secs: 0

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Homework Help Overview

The problem involves a particle's position described by the equation t = (√x) + 2, where x is in meters and t is in seconds. The task is to determine the work done by a force over the first 4 seconds, with an initial indication that the answer is 0.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find the work done by using the relationship W = F.s = mas, but expresses confusion due to the absence of force or mass information. Other participants inquire about the details of the work done so far and suggest examining the displacement of the particle.

Discussion Status

The discussion is ongoing, with some participants clarifying concepts related to displacement and its role in calculating work. There is acknowledgment of a misunderstanding regarding the initial and final positions of the particle, which may influence the work calculation.

Contextual Notes

Participants are discussing the implications of the particle's position remaining constant, which leads to questions about the displacement being zero. There is also a note about the need for additional details regarding the work done so far.

Bhumanyu Arun
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1. The position x of a particle moving along x-axis at time t is given by the eqn, t=(√x)+2.,where x is in m and t is in s. Find the work done by force in first 4 sec2. W=F.s=mas

I first found out x using the given eqn nd then went blank as there was no force or mass given. But the ans is 0
 
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Please keep the formatting headers in place when you post a homework problem.

Can you supply the details about work you've done so far? (show your equations) There may be some answers to your stated issues hidden in plain sight :wink:
 
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Bhumanyu Arun said:
2. W=F.s=mas
Here s is 'displacement' of the particle i.e. "change" in the value of 'x' in the equation. Does that ring any bells?
 
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cnh1995 said:
Here s is 'displacement' of the particle i.e. "change" in the value of 'x' in the equation. Does that ring any bells?
Great, got it. There ain't no displacement. Coz the initial as well as final position is 2. Thanx sir.
 
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Thnx for clearing my stuff everyone. Hope to get ur support always
 
Bhumanyu Arun said:
Coz the initial as well as final position is 2.
Its 4 actually..But its great you got the concept!:smile:
Bhumanyu Arun said:
Thanx sir.
I'm a student, probably of your age,20:smile:.
 
That was such a silly mistake. Well I m 2 years younger.
 

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