Work Done on 12kg Mass: 52N - 15N over 24m

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Homework Help Overview

The discussion revolves around calculating the work done on a 12 kg mass subjected to a force of 52 N while overcoming a frictional force of 15 N over a distance of 24 m. The context involves concepts of work, net force, and friction in physics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the applied force and friction, questioning whether to subtract the frictional force from the applied force to find the work done. There is discussion about the interpretation of work done by friction versus net force.

Discussion Status

The conversation includes attempts to clarify the correct approach to calculating work done against friction. Some participants suggest directly calculating the work done by friction, while others express uncertainty about the implications of using net force.

Contextual Notes

Participants are navigating the definitions of work and the role of friction in energy conservation, with some ambiguity regarding the correct method to apply in this scenario.

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Homework Statement


A force of 52 N is applied to a 12 kg mass resting on a bench where the force of sliding friction is 15 N. The work done in overcoming friction while moving the object 24 m is


Homework Equations


w=fd


The Attempt at a Solution


could i just subtract 15N from 52N, then multiply that number by 24m to find the work??
 
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Why subtract? 52-15 would be the net force on the object, so if you plug that into W=Fd, you'd find the block's final kinetic energy. You want the work done by friction--which, because of the conservation of energy, is equal to the work done in overcoming friction.
 
dance_sg said:

Homework Statement


A force of 52 N is applied to a 12 kg mass resting on a bench where the force of sliding friction is 15 N. The work done in overcoming friction while moving the object 24 m is


Homework Equations


w=fd


The Attempt at a Solution


could i just subtract 15N from 52N, then multiply that number by 24m to find the work??
The work done in overcoming friction = frictional force X displacement.
 
so all i do is multiply 15N by 24m??
 
Yes, that's the work done by friction.
 

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