Is the Work Calculation for Overcoming Friction Correct?

[Brittykitty]

A force of 52 N is applied to a 12 kg mass resting on a bench where the force of sliding friction is 15 N. The work done in overcoming friction while moving the object 24 m is


w=fd
w=(37N)(24m)
w=888J


Does this procedure seem correct ? :) Thank you!

 

[PhanthomJay]

No. You have calculated the net force and net (total) work done on the object. The total work done on the object includes the work done by the applied 52 N force, and the work done by the friction force. The work done to overcome friction is the work necessary to keep the object moving at constant velocity.

 

[Brittykitty]

What formula would I use to find the work done to overcome friction? I sort of understand but am still a bit confused

 

[PhanthomJay]

The work done to overcome friction while moving the block 24 m is the negative of the work done by friction while moving the block 24 m.

 

[Brittykitty]

So it would be -888J?

 

[Brittykitty]

24m*15N=360?

 

[PhanthomJay]

24m*15N=360?

360 J, yes.