Work Done on Sled by Rope in 15s: kJ Answer

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SUMMARY

The discussion focuses on calculating the work done by a rope on a sled being dragged at a constant speed of 1.5 m/s over a time interval of 15 seconds. The sled has a total weight of 470 N and the tension in the rope is 230 N, inclined at an angle of 30.0° to the horizontal. To find the work done, the formula W = F * d * cos(θ) is applied, where F is the tension in the rope, d is the distance traveled, and θ is the angle of inclination. The calculated work done by the rope is expressed in kilojoules (kJ).

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  • Knowledge of trigonometric functions, particularly cosine.
  • Ability to perform unit conversions, specifically from joules to kilojoules.
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natedebar72
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I need help on total work...

2. [GRR1 6.P.002.] A sled is dragged along a horizontal path at a constant speed of 1.5 m/s by a rope that is inclined at an angle of 30.0° with respect to the horizontal (the figure below). The total weight of the sled is 470 N. The tension in the rope is 230 N. How much work is done by the rope on the sled in a time interval of 15.0 s?
I need the answer in kJ
 
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What have you done so far ?
Show us your calculations.

What's the formula you apply in order to calculate the work ? What two quantities do you need to know in order to be able to apply this formula.

HINT one of the quantities has been given, you need to calculate the other one yourself.

marlon
 

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