Work, Energy and power questions

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SUMMARY

The discussion focuses on calculating the maximum speed of a 12kg mass pulled by a 500W motor over 10 seconds, and the potential and kinetic energy of a pendulum bob. The correct approach for the motor question involves using the formula Power = Work/Time, rather than P = F*v, which misinterprets the force involved. For the pendulum, the calculations for potential energy loss and maximum speed are correctly derived using the equations deltaEp = mg*h and Ek = 1/2 * mass * speed^2, yielding a maximum speed of 1.4 m/s when returning to the resting position.

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A 500w motor is used to pull a 12kg mass along a level surface from rest. If the motor is on for 10 seconds, what is the maximum speed that the mass can reach?
p=fs which i rearranged to s=p/f so to work out the force i did 12*9.81=117.72, so I put into the equation s=500/117.72=4.25
Have i done this question right?

And also another question on my homework which I'm not too sure about is:
A pendulum bob of mass 200g is raised 10cm above its resting position and allowed to swing freely. Calculate (a) its loss of potential energy in returning to its resting position (b) its maximum speed as it returns to its resting position (c) its speed when it is 5cm above resting position.
(a)
deltaEp=mg*h or W=fs
0.2x9.81=1.962
deltaEp=1.962*0.1=0.1962j

(b)
Ek=1/2mass*speed^2
speed^2=Ek / 1/2mass
speed^2=0.1962/0.1
speed^2=1.962
speed=1.4ms^-1

(c)
deltaEp=1.962*0.05
deltaEp=0.0981J
speed^2=0.0981/0.025
speed=1.98ms^-1

thanks in advance :)
 
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A 500w motor is used to pull a 12kg mass along a level surface from rest. If the motor is on for 10 seconds, what is the maximum speed that the mass can reach?
p=fs which i rearranged to s=p/f so to work out the force i did 12*9.81=117.72, so I put into the equation s=500/117.72=4.25
Have i done this question right?
No. The F in P = F*v is the force pushing the object, not the force of gravity. That formula isn't all that useful in this question. Maybe begin with Power = work/time. No friction?
 

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