Question on work energy and power kinetic energy of an ....

In summary, the conversation is about finding the original speed of a vehicle when its kinetic energy is doubled due to an increase in speed by 2m/s. The solution involves using the equation for kinetic energy and equating the initial and final kinetic energies. After solving a quadratic equation, it is determined that the original speed of the vehicle is 2(√2+1).
  • #1
Mr.maniac
38
0

Homework Statement


If the speed of a vehicle increases by 2m/s then it's kinetic energy is doubled. Find out the original speed of the vehicle

Homework Equations


1/2(mv^2)

The Attempt at a Solution


First find out both KE(kinetic energy) taking u(initial vel.)
And v(final vel.) And mass as m
K(initial KE)= 1/2(mu^2)
K`(final KE)=1/2(mv^2)
=1/2[m(u+2)^2]. {Given "speed of vehicle increases by 2m/s}

Also
2K=K`
Then equating
2[1/2(mu^2)]=1/2[m(u+2)^2].
=>mu^2=1/2(mu^2+4m+4mu)
=>u^2=1/2(u^2+4+4u) {dividing m on both sides}
=>2u^2=u^2+4+4u
=>0= -u^2+4+4u.
{Further using quadratic formula}
We get
u=(√2+1)÷2
Sadly that ain't there in the options so. :~( {booo}
 
Physics news on Phys.org
  • #2
Mr.maniac said:

Homework Statement


If the speed of a vehicle increases by 2m/s then it's kinetic energy is doubled. Find out the original speed of the vehicle

Homework Equations


1/2(mv^2)

The Attempt at a Solution


First find out both KE(kinetic energy) taking u(initial vel.)
And v(final vel.) And mass as m
K(initial KE)= 1/2(mu^2)
K`(final KE)=1/2(mv^2)
=1/2[m(u+2)^2]. {Given "speed of vehicle increases by 2m/s}

Also
2K=K`
Then equating
2[1/2(mu^2)]=1/2[m(u+2)^2].
=>mu^2=1/2(mu^2+4m+4mu)
=>u^2=1/2(u^2+4+4u) {dividing m on both sides}
=>2u^2=u^2+4+4u
=>0= -u^2+4+4u.
{Further using quadratic formula}
We get
u=(√2+1)÷2
Sadly that ain't there in the options so. :~( {booo}
Check your work in using the quadratic formula.
 
  • #3
Will do
 
  • #4
OK redid it made a slight mistake but it's still no good

u=(-1+/-√2)÷2
 
  • #5
The +/- means plus or minus or this ± sorry didn't notice the sign before
 
  • #6
Mr.maniac said:
OK redid it made a slight mistake but it's still no good

u=(-1+/-√2)÷2
That's also wrong.

Show your steps.

(The initial try looked better.)
 
  • #7
Mr.maniac said:
=>0= -u^2+4+4u.
{Further using quadratic formula}
We get
u=(√2+1)÷2
Your quadratic looks good, but redo your application of the quadratic formula.

(Edit: SammyS beat me to it!)
 
  • #8
OK got the mistake the ans now is 2(√2+1)
Which is correct I was taking the denominator wrong thank you very much for pointing that out
 
  • #9
Thank you all for helping
 

1. What is work, energy, and power?

Work is the application of force to move an object over a distance. Energy is the ability to do work, and power is the rate at which work is done or energy is transferred.

2. How is kinetic energy related to work and power?

Kinetic energy is the energy an object possesses due to its motion. It is related to work and power because work is required to change an object's kinetic energy, and power is the rate at which that work is done.

3. What is the formula for calculating kinetic energy?

The formula for calculating kinetic energy is KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

4. How does an object's mass and velocity affect its kinetic energy?

The greater an object's mass and velocity, the greater its kinetic energy. This is because kinetic energy is directly proportional to both mass and the square of velocity.

5. Can kinetic energy be converted into other forms of energy?

Yes, kinetic energy can be converted into other forms of energy, such as potential energy or thermal energy, depending on the situation. This is due to the principle of conservation of energy, which states that energy cannot be created or destroyed, only transferred or converted into different forms.

Similar threads

  • Introductory Physics Homework Help
Replies
3
Views
271
  • Introductory Physics Homework Help
Replies
6
Views
308
  • Introductory Physics Homework Help
Replies
21
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
799
  • Introductory Physics Homework Help
Replies
7
Views
906
  • Introductory Physics Homework Help
Replies
19
Views
672
  • Introductory Physics Homework Help
Replies
1
Views
726
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
468
  • Introductory Physics Homework Help
Replies
3
Views
1K
Back
Top