• Support PF! Buy your school textbooks, materials and every day products Here!

Work, energy stored in solid sphere

  • Thread starter mathnerd15
  • Start date
  • #1
109
0

Homework Statement


Find the energy stored in a uniformly charged sphere of charge q, radius R

Homework Equations





The Attempt at a Solution


[tex]Ein=\frac{qr}{4\pi\epsilon o R^3}, Eout=\frac{q}{4\pi\epsilon o r^2}... W=\int_{0}^ {R}\int_{0}^{2\pi}\int_{0}^{\pi}[\frac{qr}{4\pi\epsilon oR^3}] ^2sin\theta d\theta d\phi r^2\ dr+ \int_{R}^ {\infty }\int_{0}^{2\pi}\int_{0}^{\pi}[\frac{q}{4\pi\epsilon or^2}] ^2sin\theta d\theta d\phi r^2\ dr= 2\pi\epsilon o(\frac{q}{4\pi\epsilon o})^2(\frac{1}{5R}+\frac{1}{R})=\frac{q^2}{4\pi\epsilon o R}\frac{3}{5}[/tex]

by the way the work in this case is also like the effort needed to bring the whole solid sphere in from infinity by point charges or also the stored energy?

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
Simon Bridge
Science Advisor
Homework Helper
17,848
1,645
Is this a uniforms sphere of charge (i.e. as you may find in an insulator), or a spherical shell of charge (i.e. the charges are being placed on a conductor)? It affects the integral.

But yep - the electrostatic energy stored in a system of charges is the work needed to assemble them from infinity.

Nice LaTeX ... you can make a newline with a \\ to avoid running off the end of the page;
you can make subscripts with _{} like this: ##\epsilon_0## and ##E_{out}##.
trig functions are written \sin \cos etc.
 
  • #3
109
0
thanks! this is a solid sphere of charge. I'm curious how you develop the mathematics for this, is it based on a physical intuition or a mathematical result of the electric field equation
 
Last edited:
  • #4
Simon Bridge
Science Advisor
Homework Helper
17,848
1,645
OK... you seem to be using:
$$U=\int_V E^2d\tau + \int_S VEda$$
... it's a good idea to explain your process.

You ended up with: $$U=\frac{1}{2k}k^2q^2\left( \frac{1}{5R}+\frac{1}{R}\right)$$ ... where ##k=1/4\pi\epsilon_0##

Your next step is to simplify the expression.
Did you have any other questions?
 

Related Threads on Work, energy stored in solid sphere

  • Last Post
Replies
1
Views
332
Replies
1
Views
4K
Replies
3
Views
295
  • Last Post
Replies
1
Views
14K
  • Last Post
Replies
18
Views
96K
  • Last Post
Replies
0
Views
1K
  • Last Post
Replies
17
Views
2K
Replies
4
Views
9K
Replies
17
Views
1K
Replies
1
Views
5K
Top