Work Energy Theorem: Delta K Calculation for Particle Moving in x Direction

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SUMMARY

The discussion focuses on calculating the change in kinetic energy (Delta K) for a particle moving under the influence of a net force defined as F(x) = Cx², where C is a constant. The particle transitions from an initial position of x = L to a final position of x = 3L. The correct approach involves finding the anti-derivative of the force function and evaluating it over the specified interval, leading to the conclusion that the correct Delta K is 8/3 CL³, correcting the initial miscalculation of 2/3 CL³.

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  • Understanding of the Work Energy Theorem
  • Knowledge of integration techniques in calculus
  • Familiarity with force functions and their anti-derivatives
  • Basic concepts of kinetic energy in physics
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Physics students, educators, and anyone interested in understanding the application of the Work Energy Theorem in calculating kinetic energy changes for particles under variable forces.

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A particle moving in the x direction is being acted upon by a net force F(x)=Cx^2, for some constant C. The particle moves from x initial =L to x final=3L. What is Delta K, the change in kinetic energy of the particle during that time?

I tried thih by doing the integral of F(x), replacing x with 2L (because final-initial, 3L-L). I got the answer 2/3 CL^3, and its telling me I am off by a multiplicative factor. Is this because I did the integral wrong, or am I missing something?

Thanks!
 
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Not sure what you did or what you mean by "replacing x with 2L". Step 1: Find the anti-derivative. Step 2: Evaluate it over the interval x = L to x = 3L. (Evaluate for x = 3L and for x = L and subtract.)
 

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