Work in a thermodynamic process

AI Thread Summary
The discussion revolves around a physics problem involving a projectile launched by expanding gas, with specific parameters for pressure and volume. The user calculates the work done by the gas and the kinetic energy of the projectile, arriving at a speed of 48 m/s and determining that two-thirds of the work is used to push air out of the way when launched into air. There is a note that the forum typically encourages deeper engagement through questions rather than simply validating answers. The user seeks confirmation of their calculations and expresses uncertainty about certain steps. Overall, the calculations appear to be methodical, though the community emphasizes the importance of understanding the underlying concepts.
RslM
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Hello, could someone please let me know if I have worked this problem out correctly, or if I need to try again? Thank you.

Homework Statement


A 40.0 g projectile is launched by the expansion of hot gas in an arrangement showing in Figure P12.4a (attached file). The cross-sectional area of the launch tube is 1.0 cm2, and the length that the projectile travels down the tube after starting from rest is 32 cm. As the gas expands, the pressure varies as shown in Figure P12.4b. The values for the initial pressure and volume are Pi = 11 x 105 Pa and Vi = 8.0 cm3 while the final values are Pf = 1.0 x 105 Pa and Vf = 40.0 cm3. Friction between the projectile and the launch tube is negligible.

A) If the projectile is launched into a vacuum, what is the speed of the projectile as it leaves the launch tube?

B) If instead the projectile is launched into air at a pressure of 1.0 x 105 Pa, what fraction of the work done by the expanding gas in the tube is spent by the projectile pushing air out of the way as it proceeds down the tube?



Homework Equations



I chose to use:
Work = the area under a curve
KE = 1/2mV2

The Attempt at a Solution



Area under the curve:

Pi = 11 x 105 Pa
Pf = 1.0 x 105 Pa

Vi = 8.0 cm3
Vf = 40.0 cm3

ΔP = 1.0 x 105 Pa - 11 x 105 Pa = -10 x 105 Pa

ΔV = 40 cm3 - 8.0 cm3 = 32 cm3
= 3.2 x 10-5 m3

Area of triangle under curve = (1/2)(-10 x 105 Pa)(3.2 x 10-5 m3) = -16 J

Area of rectangle under curve = (-1.0 x 105 Pa)(3.2 x 10-5 m3) = -32 J

W = -32 J + (-16 J) = -48 J


KE = 1/2mv2

v = √(2KE/m)

KE = 48 J
m = 0.040 kg

V = √((2(48J))/0.040 kg) = 48 m/s

B) W = (-1.0 x 105 Pa)(3.2 x 10-5 m3) = -32 J

-32 J/-48 J = 2/3

2/3 of the work done by the expanding gas in the tube is spent by the projectile pushing air out of the way as it proceeds down the tube.
 

Attachments

  • P12.4ab.jpg
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No replies so far, perhaps because your question isn't quite legit within PF. PF helpers help to come closer to a solution by asking questions and giving hints. PF is not about ensuring eveyone scoring an A+ by stamp-approving their work.
That being said, you've done the work, found an answer, checked it. Is there something you have checked that you think doesn't fit ? Some small step you feel unsure about ?
 
Thank you for the reply.
 
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