Can I Combine X and Y Components in the Work Equation?

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To calculate the work done on the car, the force components must be combined using the dot product with the displacement vector. The relevant equation for work is W = F · S, where F is the force vector and S is the displacement vector. In this case, the x component of the force is 5.33 N, and the y component is 4.42 N, while the displacement along the y-axis is 0 m. Therefore, the work done can be calculated as (5.33 N * 3.4 m) + (4.42 N * 0 m). The final result will yield the total work done in joules.
Tinkylo
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Homework Statement
If you apply a force F with the x component =5.33 N and the y component = 4.42 N on a car which moves along the x-axis by a displacement of 3.4 m. What is the work done on the car by your force in J?
Relevant Equations
work= F x S
I don't know how to combine the x,y components with the equation of work.
 
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Tinkylo said:
Homework Statement:: If you apply a force F with the x component =5.33 N and the y component = 4.42 N on a car which moves along the x-axis by a displacement of 3.4 m. What is the work done on the car by your force in J?
Relevant Equations:: work= F x S

I don't know how to combine the x,y components with the equation of work.
Force and displacement are vectors. How is work defined in terms of these vectors?
 
work is the dot product of the vector of force snd displacement.
 
Tinkylo said:
work is the dot product of the vector of force snd displacement.
Yes. So, use that.
 
That's mean the expression will be (5.33Nx3.4m)+(4.42N x0m)?
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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