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**1. The problem statement, all variables and given/known data**

The coefficient of kinetic friction between a 20kg box and the floor is 0.40 -> How much work does a pulling force applied 37 degrees above the horizontal do on the box in pulling it 8.0m across the floor at constant speed

**2. Relevant equations**

F(kinetic)= F(normal) x U(kinetic)

W=Fxd

Fx=Fcos(theta)

**3. The attempt at a solution**

I solved for kinetic friction, I'm just not 100% sure where to go next, a hint would be more helpful in the long run than the answer to the entire question... I was thinking of assuming that force in the x direction should be equal to F(kinetic) and then just multiplying f(kinetic) by the distance 8 metres... Nonetheless I feel like there is more to it....