Work (of worker, gravity, normal, total)

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SUMMARY

The discussion focuses on calculating the work done on a 25.0 kg crate being pushed up a frictionless incline at an angle of 25.0°. The worker exerts a force of 209 N parallel to the incline, resulting in 314 J of work done by the worker's applied force. The gravitational force contributes -155 J, while the normal force does no work (0 J) as it acts perpendicular to the movement. The total work done on the crate is calculated to be 159 J.

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This is my first problem set involving work, so I want to make sure I'm doing it right. Thanks for checking.

Homework Statement


To push a 25.0 kg crate up a frictionless incline, angled at 25.0° to the horizontal, a worker exerts a force of magnitude 209 N parallel to the incline. As the create slides 1.50 m, how much work is done on the crate by (a) the worker's applied force, (b) the gravitational force on the crate, and (c) the normal force exerted by the incline on the create? (d) What is the total work done on the crate?


Homework Equations


W=Fdcos\theta
Fg=mg

The Attempt at a Solution



A) W=209*1.50*cos0
=313.5
=314 J

B) Wg=Fdcos\theta
=(9.8*2.50)*1.5*cos(115)
=-155.31
=-155. J

C) 0 J, since Fn is always perpendicular to movement along flat surface

D) Wnet=Wa+Wb+Wc...
=314-155
=159 J
 
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