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## Homework Statement

1. A 1250 Kg piledriver falls from an initial height of 1.30m above the ground onto a 15kg spike the top of which is initially 0.30m above the ground. The top of the spike finishes at ground level. Determine the average force exerted on the piledriver by the spike.

*Pd=Piledriver

S=Spike

mass of piledriver= 1250kg

h1= 1.3m

h2=0m

g=9.8m/s2

mass of spike=15kg

h1=0.30m

## Homework Equations

Fnet=F1+F2...

## The Attempt at a Solution

Fnet=Fn(S) + Fg(Pd)

= (15*9.8) + (1250*9.8)

=12397 N

Average=

__(FnS –FgPd) = FgPd__

2= FnS /2

= (15*9.8) /2

=73.5 N

Fnet=Fn(S) + Fg(Pd)

= (15*9.8) + (1250*9.8)

=12397 N

therefore, the average force applied on the piledriver by the spike is 73.5N

* i really,reallly, really could use some assistance on this one. its grade 11 physics, so i know it can't be that hard. Any Suggestions?

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