- #1

JoeyBob

- 256

- 29

- Homework Statement
- See attached

- Relevant Equations
- Ek=1/2mv^2 Ep=1/2 k (x)^2

First calculated non conservative work from friction using Ff=umg. Non conservative work was -8.82.

Initial kinetic energy, 1/2mv^2, was 136.89.

Change in potential energy, 1/2k(x)^2, was 8.1216.

Ekf-Eki+Change Ep=Work NC

Ekf=W NC+Eki-change Ep

=-8.82+136.89-8.1216=119.9484

Ekf=1/2mv^2, v=7.3014 but answer should be 7.44. I've confirmed there were no rounding errors by trying the same calculation all at once in the calculator (I still get 7.3).

Initial kinetic energy, 1/2mv^2, was 136.89.

Change in potential energy, 1/2k(x)^2, was 8.1216.

Ekf-Eki+Change Ep=Work NC

Ekf=W NC+Eki-change Ep

=-8.82+136.89-8.1216=119.9484

Ekf=1/2mv^2, v=7.3014 but answer should be 7.44. I've confirmed there were no rounding errors by trying the same calculation all at once in the calculator (I still get 7.3).