Calculating Work Done by Gravity on a 21N Book Falling and Moving on a Shelf

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SUMMARY

The discussion focuses on calculating the work done by gravity on a 21N book in three scenarios: falling, being lifted, and sliding horizontally. The work done when the book falls 3 meters is 63 Joules, as the force of gravity and displacement are in the same direction. Conversely, when lifting the book back to the shelf, the work done is -63 Joules due to the opposing directions of force and displacement. Sliding the book horizontally results in zero work done, as there is no vertical displacement.

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  • Familiarity with gravitational force concepts
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  • Ability to differentiate between positive and negative work
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Homework Statement



- A book has a weight of 21N. It falls off the shelf on to the floor, 3 m below. The work done by the force of gravity is what?

- A book has a weight of 21N. You pick it up off the floor, and return it to the shelf, 3 m above. The work done by the force of gravity is what?

- A book has a weight of 21N. You slide it horizontally along the shelf, a distance of 3 m. The work done by the force of gravity is what?


Homework Equations



Work = Force x Distance



The Attempt at a Solution



I don't get the differences, please help!
 
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Hello, Well you understand that Work=Force*distance. well let's look at this problem in this way, If a force is applied to an object, and that object slides in the direction of the displacement then the work is positive. so the first one should be W=63 Joules downward. because 21N*3m. Since the displacement (downward) is in the same direction as the force (gravity downward) then work is positive. The person picking up the book is different because the work is the same however since the displacement (upward) is in the opposite direction as the force (gravity downward) then work is negative. One important thing about work is that if there is no component of force in the direction of displacement then the Work is zero. So for the work of the guy sliding the book horizontally is zero. Hope that helps
 
Thanks so much, that's much more clear. So basically the answer for the first question is 63 J, the answer for the second is -63 J and the answer for the last one is 0?
 
Yessir! Glad it makes sense
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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