MHB Work Rate Problem: 4 Men, 9 Women in 13.388 Days

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The discussion revolves around calculating the time it takes for 4 men and 9 women to complete a job, given that 18 men or 20 women can finish it in 9 days. The original poster calculated the time as approximately 13.388 days, using the work rates of men and women. However, there is confusion regarding the accuracy of this answer, as another participant points out that the book states the answer is 6 1/20 days. The discrepancy arises from the understanding of work rates, with the consensus that the book's answer seems incorrect based on the provided data. The calculations confirm that the original solution is indeed correct.
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If 18 men or 20 women can do a work in 9 days, in what time can 4 men and 9 men do the same work?

My attempt

D = days required

4/162 + 9/180 = 1/D

D = 13.388 days

Is my solution correct?

Thanks!
 
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NotaMathPerson said:
If 18 men or 20 women can do a work in 9 days, in what time can 4 men and 9 men do the same work?

My attempt

D = days required

4/162 + 9/180 = 1/D

D = 13.388 days

Is my solution correct?

Thanks!

4 men and 9 men?
 
NotaMathPerson said:
If 18 men or 20 women can do a work in 9 days, in what time can 4 men and 9 men do the same work?

My attempt

D = days required

4/162 + 9/180 = 1/D

D = 13.388 days

Is my solution correct?

Thanks!

From your working, I assume the question is actually:

"In what time can 4 men and 9 women do the same work?"

Your method is good, and the solution correct. A single man will take 162 days to complete the work, while a single woman will take 180 days. So, the amount of the job done by each man in a day is 1/162 and for a woman 1/180, and so with 4 men and 9 woman working, the amount done is:

$$\frac{4}{162}+\frac{9}{180}=\frac{121}{1620}$$

and since this is one day's work, this is equal to 1/D of the work. Hence:

$$D=\frac{1620}{121}\approx13.388$$
 
MarkFL said:
From your working, I assume the question is actually:

"In what time can 4 men and 9 women do the same work?"

Your method is good, and the solution correct. A single man will take 162 days to complete the work, while a single woman will take 180 days. So, the amount of the job done by each man in a day is 1/162 and for a woman 1/180, and so with 4 men and 9 woman working, the amount done is:

$$\frac{4}{162}+\frac{9}{180}=\frac{121}{1620}$$

and since this is one day's work, this is equal to 1/D of the work. Hence:

$$D=\frac{1620}{121}\approx13.388$$

Hello!

The answer in my book says it is $6\frac{1}{20}$ days. Why is that?
 
NotaMathPerson said:
Hello!

The answer in my book says it is $6\frac{1}{20}$ days. Why is that?

If it takes 18 men 9 days to do the work, does it make any sense that it would take 13 people, 9 of which are women (who take slightly longer to do the work) a smaller amount of time?

Did you give the problem exactly as stated?
 
MarkFL said:
If it takes 18 men 9 days to do the work, does it make any sense that it would take 13 people, 9 of which are women (who take slightly longer to do the work) a smaller amount of time?

Did you give the problem exactly as stated?

View attachment 5659

Here is the question from the book. This is from a section of ratio and proportion.
 

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That answer would make sense if it took 11 men 4 days to do the job and 11 women need 11 days to do the job. But as given, the answer supplied with the problem is just wrong. :)
 
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