Work Rate Problem: 4 Men, 9 Women in 13.388 Days

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SUMMARY

The work rate problem involves calculating the time required for 4 men and 9 women to complete a task, given that 18 men or 20 women can finish the work in 9 days. The correct calculation shows that 4 men and 9 women can complete the work in approximately 13.388 days. The breakdown reveals that a single man completes the work in 162 days, while a single woman takes 180 days. The method used to derive the solution is validated by multiple participants in the discussion.

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NotaMathPerson
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If 18 men or 20 women can do a work in 9 days, in what time can 4 men and 9 men do the same work?

My attempt

D = days required

4/162 + 9/180 = 1/D

D = 13.388 days

Is my solution correct?

Thanks!
 
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NotaMathPerson said:
If 18 men or 20 women can do a work in 9 days, in what time can 4 men and 9 men do the same work?

My attempt

D = days required

4/162 + 9/180 = 1/D

D = 13.388 days

Is my solution correct?

Thanks!

4 men and 9 men?
 
NotaMathPerson said:
If 18 men or 20 women can do a work in 9 days, in what time can 4 men and 9 men do the same work?

My attempt

D = days required

4/162 + 9/180 = 1/D

D = 13.388 days

Is my solution correct?

Thanks!

From your working, I assume the question is actually:

"In what time can 4 men and 9 women do the same work?"

Your method is good, and the solution correct. A single man will take 162 days to complete the work, while a single woman will take 180 days. So, the amount of the job done by each man in a day is 1/162 and for a woman 1/180, and so with 4 men and 9 woman working, the amount done is:

$$\frac{4}{162}+\frac{9}{180}=\frac{121}{1620}$$

and since this is one day's work, this is equal to 1/D of the work. Hence:

$$D=\frac{1620}{121}\approx13.388$$
 
MarkFL said:
From your working, I assume the question is actually:

"In what time can 4 men and 9 women do the same work?"

Your method is good, and the solution correct. A single man will take 162 days to complete the work, while a single woman will take 180 days. So, the amount of the job done by each man in a day is 1/162 and for a woman 1/180, and so with 4 men and 9 woman working, the amount done is:

$$\frac{4}{162}+\frac{9}{180}=\frac{121}{1620}$$

and since this is one day's work, this is equal to 1/D of the work. Hence:

$$D=\frac{1620}{121}\approx13.388$$

Hello!

The answer in my book says it is $6\frac{1}{20}$ days. Why is that?
 
NotaMathPerson said:
Hello!

The answer in my book says it is $6\frac{1}{20}$ days. Why is that?

If it takes 18 men 9 days to do the work, does it make any sense that it would take 13 people, 9 of which are women (who take slightly longer to do the work) a smaller amount of time?

Did you give the problem exactly as stated?
 
MarkFL said:
If it takes 18 men 9 days to do the work, does it make any sense that it would take 13 people, 9 of which are women (who take slightly longer to do the work) a smaller amount of time?

Did you give the problem exactly as stated?

View attachment 5659

Here is the question from the book. This is from a section of ratio and proportion.
 

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That answer would make sense if it took 11 men 4 days to do the job and 11 women need 11 days to do the job. But as given, the answer supplied with the problem is just wrong. :)
 

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