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Working out Zero-Point Energy and ration of potential to kinetic for a particle.

  • Thread starter Epideme
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Homework Statement


Consider a particle with mass, m moving in one dimensional potential U=kx^2/2 as in a mass-spring system. The total energy of the particle is

E= (p^2/2m) + (kx^2/2)

Classically, the absolute minimum of the enrgy, E=0 is acheived when p=0 and x=0. In quantum mechanics however, the momentum, p and the co-ordinate x cannot simulataneously have certain valus. Using the heisenberg uncertainty relation:

a)Calculate the minimum possible value of energy, E. This lowest possible energy, which is not zero, is called zero-point energy.
b)What is the ratio of kinetic to the potential enrgy of the particle in a state of minimal total energy


Homework Equations


Delta x delta p = hbar / 2 <---Hesinberg Uncertainty Principle



The Attempt at a Solution


I'm completely lost, with all the remaining 4 questions of my work which i'm posting.
 

Answers and Replies

  • #2
malawi_glenn
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I don't think that one can be completely lost, never.

If one has no idea, then one usually make a competent guessing, try it.
 
  • #3
tiny-tim
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help plzzzz!

I don't think that one can be completely lost, never.
:smile: I'm completely lost. :confused:

Which thread am I supposed to be in? :cry:
 
  • #4
malawi_glenn
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:smile: I'm completely lost. :confused:

Which thread am I supposed to be in? :cry:
You have to provide an attempt to solution :rolleyes:

Please make a new thread if you want to ask a question
 
  • #5
tiny-tim
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You have to provide an attempt to solution :rolleyes:
Well, I the last thing I remember is turning left at the Library, and heading towards Special & General Relativity :smile:

after that it's all a blur :redface:

do you think I travelled faster than light? :confused:
 

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