MHB Working with time and dropping from a specified height

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To determine how long it takes for a drop of paint to hit the ground from a height of 225 feet, the relevant physics formula incorporates the distance, initial velocity, and acceleration due to gravity. Given that the initial velocity is 0 and the acceleration is 32.2 ft/s², the formula to calculate time is t = √(2ad + v₀²). Plugging in the values, the equation simplifies to t = √(2 * 32.2 * 225). This calculation yields the time it takes for the paint to reach the ground, demonstrating the application of kinematic equations in free fall scenarios. Understanding these principles is essential for solving similar physics problems.
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hello there! I've been working on math for a while, and on y math homework there's a specific question that i just don't know of the correct formula to solve it. i can do algebra quite well, i just can't recall what this specific formula may be. here is my question:
A construction worker is working on the roof of a building. a drop of paint falls from a rafter that is 225 feet about the ground. after how many seconds does the paint hit the ground?
 
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If we ignore drag, then a freefalling body near the surface of the Earth experiences a constant acceleration of about 32.2 ft/s/s. So, we know the distance $d$ (225 ft), the initial velocity $v_0 = 0$, and the acceleration $a$, and we need the time to cover that distance. A useful formula is thus:

$$t=\sqrt{2ad+v_0^2}$$

Can you proceed?
 
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