Would two conductors of same charge touch or not touch?

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SUMMARY

In the discussion regarding the interaction of two conductors with the same charge, it is established that they will not touch due to the repulsive forces between like charges. The participants analyzed the effects of gravity on the motion of the conductors, concluding that while gravity influences their velocity, it does not negate the repulsion caused by identical charges. The key takeaway is that conductors allow charge mobility, which enhances the repulsion effect as they approach each other.

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Homework Statement


insulating_spheres.png


Homework Equations


I need help with part c

for part (a) I got 18 m/s and for part (b) I said the velocity would be zero after a long time has passed, assuming that there is gravity.

The Attempt at a Solution


For part (c) I would assume that they would not touch because they are conductors of the same charge and same charge would not attract. I'm not sure if that is correct though.

Thanks!
 
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notaphysmajor said:
...for part (a) I got 18 m/s and for part (b) I said the velocity would be zero after a long time has passed, assuming that there is gravity.
Why does gravity make a difference? Are you thinking that q2 falls to the ground?
When you did part (a), did you account for gravity? In fact - how did you do part (a)?

For part (c) I would assume that they would not touch because they are conductors of the same charge and same charge would not attract. I'm not sure if that is correct though.
For part (a), identical charge, you said that the sphere do touch if they go fast enough. Thus, merely being the same charge is not enough to prevent them crashing into each other.

The main difference between a conductor and an insulator for this situation is that the charges on a conductor are free to move around the conductor. The charges do repel each other ... so sketch the two sphere's close to each other and sketch the charge distribution across the surface of both.
Compare with the case that the charges are evenly distributed - think about the strength of the repulsion for the same separation.
 
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