Write the electron configuration of Cd2+

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Discussion Overview

The discussion revolves around determining the electron configuration of the cadmium ion, Cd2+. Participants explore the correct representation of the electron configuration, particularly focusing on the changes that occur when cadmium loses two electrons to form the cation.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant proposes an initial electron configuration for Cd2+ as 1s^2 2s^2 2p^6 3s^1 3p^6 3d^10 4s^2 4p^6 5s^2 4d^10.
  • Another participant challenges this configuration, stating that it appears to represent the neutral cadmium atom rather than the cation, questioning the inclusion of 3s^1.
  • A third participant clarifies that to form Cd2+, cadmium must lose two electrons from its outer shell, indicating that the initial configuration provided is incorrect for the cation.
  • Further clarification is sought regarding the correct configuration for Cd2+, with a suggestion that it should exclude the outermost electrons.
  • One participant introduces shorthand notation for the electron configuration of neutral cadmium as [Kr]5s^2 4d^10, emphasizing that this notation represents the neutral atom and reiterating the need to remove two electrons for Cd2+.

Areas of Agreement / Disagreement

Participants generally agree that the initial configuration provided is incorrect for Cd2+, but there is no consensus on the exact correct configuration, as various interpretations and corrections are proposed.

Contextual Notes

There is an emphasis on the need to remove two outer electrons to arrive at the correct configuration for Cd2+, but the specific configuration remains unresolved among participants.

jupiter_8917
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Write the electron configuration of Cd2+

Is It right if I write it like this 1s^2 2s^2 2p^6 3s^1 3p^6 3d^10 4s^2 4p^6 5s^2 4d^10?

Can anyone please correct me if it is wrong? Thank you very much!
 
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5s24d10 looks to me like neutral atom, not a cation.

Why 3s1? Is it just a typo?
 
Hi,
In order for Cd to form Cd2+, Cd has to lose its 2e- in the outer-shell. So, take a look at your configuration, you are having the configuration for the neutral Cd, you need to remove 2 outer e- to get the right configuration. And also don't forget the "reminder" from Mr. Borek about the 3s1 typo.

Good Luck!
 
do you mean it need to be like this in order to form Cd2+? 1s^2 2s^2 2p^6 3s^1 3p^6 3d^10 4s^2 4p^6

thanks again,
 
Sorry for the confusion. Electron configuration of Cd can be given as [Kr]5s24d10 - that is very convenient short hand notation, that uses noble gas configuration as its basis. Configuration of Kr is 1s22s22p63s23p64s23d104p6, so [Kr]5s24d10 means 1s22s22p63s23p64s23d104p65s24d10 - that's configuration of neutral Cd atom. I was referring to this notation and just to the last two subshells.

[Kr]5s24d10 is a configuration of the neutral atom. As it was said several times - to make Cd2+ you have to remove two electrons.
 
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