1. The problem statement, all variables and given/known data Write the ground state electron configuration of Mn2+. 2. Relevant equations N/A 3. The attempt at a solution Well I thought that since it had the 2+ superscript and manganese is a metal, it must have lost two electrons. Manganese has an atomic number of 25 and losing two electrons would put it at 23, the same as vanadium (V). Therefore, I thought that the electron configuration would be the same as vanadium: [tex]1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^3 [/tex] But I am told this is wrong, and I can't see anything else that could be the answer if Mn2+ does indeed have 23 electrons. Any help is appreciated. Thank you!