Wronskian to determine lin.ind. of solutions to a system of ODEs

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SUMMARY

The discussion centers on using the Wronskian to determine the linear independence of the solutions to a system of ordinary differential equations (ODEs). The vectors given are vec{x}_1=(t^2, t), vec{x}_2=(0, 1+t), and vec{x}_3=(-t^2, 1). The Wronskian is constructed but the user encounters difficulties in calculating the determinant, leading to the conclusion that the vectors are not linearly independent by inspection rather than through the Wronskian method.

PREREQUISITES
  • Understanding of linear independence in vector spaces
  • Familiarity with the Wronskian determinant
  • Basic knowledge of matrix operations
  • Concepts of ordinary differential equations (ODEs)
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  • Study the properties of the Wronskian determinant in detail
  • Learn how to compute determinants of 3x3 matrices
  • Explore linear independence criteria in vector spaces
  • Review examples of using the Wronskian for different sets of functions
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Students and educators in mathematics, particularly those studying linear algebra and ordinary differential equations, will benefit from this discussion.

SithsNGiggles
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Homework Statement



In my book, I'm given that ##\vec{x}_1=\left(\begin{matrix}t^2\\t\end{matrix}\right), \vec{x}_2=\left(\begin{matrix}0\\1+t\end{matrix}\right), \vec{x}_3=\left(\begin{matrix}-t^2\\1\end{matrix}\right)## are solutions. My textbook presents an algebraic way to show that the vectors are linear independent, but I was hoping to see if I can use the Wronskian to show the same result.

Homework Equations



The Attempt at a Solution



I thought this was how the Wronskian would look:
##W\left(\vec{x}_1, \vec{x}_2, \vec{x}_3\right)=

\left|\begin{matrix}

\left(\begin{matrix}t^2\\1\end{matrix}\right) & \left(\begin{matrix}0\\1+t\end{matrix}\right) & \left(\begin{matrix}-t^2\\1\end{matrix}\right)\\

\left(\begin{matrix}2t\\0\end{matrix}\right) & \left(\begin{matrix}0\\1\end{matrix}\right) & \left(\begin{matrix}-2t\\0\end{matrix}\right)\\

\left(\begin{matrix}2\\0\end{matrix}\right) & \left(\begin{matrix}0\\0\end{matrix}\right) & \left(\begin{matrix}-2\\0\end{matrix}\right)
\end{matrix}\right|##

But I couldn't see how to proceed from there, since matrix multiplication won't work. How would I find this determinant?
 
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You can't because it doesn't make sense.

In any case, you should be able to see by inspection that the three vectors aren't linearly independent.
 
Okay, thanks.
 

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