X(3600s/1hr)^2=(1.38013017E+10in/hr^2)Conversion of 9.8m/s^2 to in/hr^2

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Homework Help Overview

The discussion revolves around converting an acceleration value from meters per second squared (m/s²) to inches per hour squared (in/hr²). The original poster attempts to perform the conversion but encounters difficulties with the unit conversions, particularly with the time component.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore various conversion factors, including the relationship between feet and meters, and inches and feet. There are attempts to address the conversion of seconds to hours, with some questioning the accuracy of their calculations.

Discussion Status

Some participants have offered guidance on the correct approach to handle the time conversion, emphasizing the importance of squaring the conversion factor for seconds to hours. There is recognition of common mistakes in unit conversions, and a few participants share their realizations about errors made in the calculations.

Contextual Notes

Participants note the complexity of the conversion process and the potential for confusion when dealing with multiple units of measurement. There is an acknowledgment of the need for careful step-by-step calculations to avoid errors.

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Homework Statement



9.8m/s^2= ? in/hr^2

Homework Equations





The Attempt at a Solution



(9.8m/s^2)X(1ft/.3048m)=(9.8ft/.3048s^2)=(32.15223097ft/s^2)X(12in/1ft)=(385.8267717in/s^2)
 
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You're looking good so far. Now take care of the "seconds" in the denominator...
 
how to do the seconds

can i do (385.8267717in/s^2) X (60s^2/1hr^2) = 1388976.378in/hr^2. this answer is not correct
 
That's because, firstly, there's not 60 seconds in an hour, and secondly, you need to square this number anyway.

Think of it like the units are [tex]\frac{in}{s^2}=\frac{in}{s\cdot s}[/tex]. Now, there are 3600 seconds in an hour, so replace that in the denominator to give [tex]\frac{in}{3600^{-2}hr^2}=\frac{3600^2in}{hr^2}[/tex]
 
wiskeywiz said:
can i do (385.8267717in/s^2) X (60s^2/1hr^2) = 1388976.378in/hr^2. this answer is not correct

Cristo is correct. If you aren't fully comfortable with certain conversion factors, you may want to use more steps, as you did correctly with the portion leading from meters to inches:

(385.8267717in/s^2) X [(60 s/1 min)^2] = (385.8267717in/s^2) X (3600s^2/1 min^2) =

(385.8267717 in X (3600)/min^2) =

(385.8267717 in x (3600)/min^2) X [(60 min/1 hr)^2] =

(385.8267717 in x (3600)/min^2) X (3600 min^2/1 hr^2) =

(385.8267717 in x (3600) x (3600)/hr^2), and so on to the result. The number will be quite enormous.

You don't need to try to skip steps when you're not making a familiar calculation: leaving out steps can increase the risk of making a serious mistake.
 
i got it. i goofed when i tried being slick and figured 3600s^2 = 60^2/hr^2
 
wiskeywiz said:
i got it. i goofed when i tried being slick and figured 3600s^2 = 60^2/hr^2

Everyone does that, including faculty lecturers, who really should know better... It usually ends up saving time (and sometimes embarrassment) to work out more steps when the calculation is unfamiliar, complicated, or subtle, than trying to make leaps in your head...

Good job!
 

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