Yes, Use P-Series Test to Confirm Series Convergence

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Homework Help Overview

The discussion revolves around the convergence of a series defined by the term an = 1 / (n+1)^2, with participants exploring the application of the p-series test and comparison test in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the p-series test, questioning whether the series converges based on the value of p. There is also mention of changing the series index and comparing terms to establish convergence.

Discussion Status

Some participants affirm the convergence of the series using the p-series test, while others suggest the comparison test as an alternative approach. There is an ongoing exploration of these methods without a definitive consensus on the preferred approach.

Contextual Notes

Participants are considering the implications of using different tests for convergence and the relationships between the terms of the series. The discussion includes potential assumptions about the series' behavior based on established mathematical principles.

naspek
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if my an = 1 / (n+1)^2
can i use p series test to confirm that the series will converge..
where p = 2..
 
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Sure. If your series is something like this,
[tex]\sum_{n = 0}^{\infty} \frac{1}{(n + 1)^2}[/tex]

you can change the series index to write the series this way:
[tex]\sum_{n = 1}^{\infty} \frac{1}{n^2}[/tex]
 
it's comparison test right?
the series will converge..
am i right?
 
p-series converge for p>1, so yes, your summation converges.
 
naspek said:
it's comparison test right?
the series will converge..
am i right?
You don't need the comparison test if you know the p-series test, and this is a p-series.
 
I believe that naspek was saying that he can argue that [itex]1/(n+1)^2< 1/n^2[/itex] and so use the comparison test without using your idea of changing the index.
 

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