Zero curvature => straight line proof

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SUMMARY

The discussion centers on proving that a curve in R3 with zero curvature is a straight line. The key argument presented is that if the curvature k equals zero, then the derivative of the tangent vector dT/ds equals zero, indicating that the tangent vector T remains constant. This constancy of T confirms that the curve must be a straight line. Additionally, it is noted that zero curvature occurs when the second derivative of the curve has no normal component, reinforcing the conclusion that a parameterized curve by arc length will yield a straight line when the second derivative is zero.

PREREQUISITES
  • Understanding of curvature in differential geometry
  • Familiarity with the Serret Frenet equations
  • Knowledge of tangent vectors and their derivatives
  • Concept of parameterization of curves by arc length
NEXT STEPS
  • Study the Serret Frenet equations in detail
  • Explore the implications of curvature in differential geometry
  • Learn about the properties of tangent vectors and their derivatives
  • Investigate parameterization techniques for curves in R3
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Mathematicians, physics students, and anyone interested in differential geometry and the properties of curves in three-dimensional space.

Shaybay92
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How would you prove that if the curvature of a 'curve' in R3 is zero that the line is straight? All I have learned about is the Serret Frenet equations which I thought only apply when the curvature is non-zero? How do you define normals/binormals in this case?

I'm not sure if this is enough... but:

dT/ds = kN = 0 because k=0
this implies that T is constant at all points ,which implies a straight line?
 
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Shaybay92 said:
How would you prove that if the curvature of a 'curve' in R3 is zero that the line is straight? All I have learned about is the Serret Frenet equations which I thought only apply when the curvature is non-zero? How do you define normals/binormals in this case?

I'm not sure if this is enough... but:

dT/ds = kN = 0 because k=0
this implies that T is constant at all points ,which implies a straight line?

the curvature is zero only when the second derivative has no normal component. If you parameterize the curve by arc length then the second derivative is zero.
 

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