Zero equilibrium 0 x a force?

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SUMMARY

The discussion centers on calculating the torque required to rotate a 3-foot bar weighing 10 lbs attached to an axle, specifically to achieve rotational speeds of 30 RPM and 60 RPM. Participants highlight the necessity of applying force to overcome inertia and maintain motion, referencing the principles of torque and angular acceleration. Nema class stepper motors with gear ratios of 5:1, 16:1, or 27:1 are considered for this application, as they can achieve speeds up to 700 RPM. The conversation emphasizes the importance of understanding the relationship between torque, force, and rotational motion.

PREREQUISITES
  • Understanding of torque and its role in rotational motion
  • Familiarity with Nema class stepper motors and their specifications
  • Knowledge of gear ratios and their impact on motor performance
  • Basic principles of angular acceleration and motion dynamics
NEXT STEPS
  • Research torque calculations for rotating objects using the formula τ = r × F
  • Explore the specifications and applications of Nema class stepper motors
  • Learn about gear ratio effects on motor speed and torque output
  • Study angular acceleration and its implications for mechanical systems
USEFUL FOR

Engineers, robotics enthusiasts, and anyone involved in mechanical design or motor selection will benefit from this discussion, particularly those working with rotational systems and torque calculations.

j1ceasar
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Okay - a classic trap . multiplication times zero .
I have a 3 foot bar weighing 10 lbs . its attached along its mid point to an axle . how much torque / force - do I need along its axle ( motorized ) to get it to spin 30 rpm or 60 rpm ?

its in equilibrium , but of course it needs FORCE to move it

I am considering Nema class stepper motors / geared 5/1 - 16 to one or 27/1 - usually these motors go to 700- rpm ...
 
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j1ceasar said:
Okay - a classic trap . multiplication times zero .
I have a 3 foot bar weighing 10 lbs . its attached along its mid point to an axle . how much torque / force - do I need along its axle ( motorized ) to get it to spin 30 rpm or 60 rpm ?

its in equilibrium , but of course it needs FORCE to move it

I am considering Nema class stepper motors / geared 5/1 - 16 to one or 27/1 - usually these motors go to 700- rpm ...
Uh ... WHAT multiplication by zero?
 
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Just like F = m*a for linear motion, there is an analog for rotational motion as well. A torque will be required to accelerate the bar, but once it's moving only air drag and friction will slow it down.

See here: https://en.wikipedia.org/wiki/Angular_acceleration
 

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