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sketching a level curve |
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| Mar30-10, 03:26 PM | #1 |
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sketching a level curve
im having trouble with sketching a level curve
ex. equation: f(x,y) = x^2 + 2y^2 i cant run it .. (edit: sorry, -cant run it by matlab) .. :( cant solve cant graph cant all .... in short, cant any attempt at a solution :((( thank for your help .. |
| Mar30-10, 03:30 PM | #2 |
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Level curves are two-dimensional slices of a surface in three dimensions. Pick several values for z and sketch graphs of the resulting curves. For example, if z = 0, what's the graph of the equation x^2 + 2y^2 = 0 look like? If z = 1, what's the graph of the equation x^2 + 2y^2 = 1 look like? If z = -1, what's the graph of the equation x^2 + 2y^2 = -1 look like? And so on... |
| Mar30-10, 03:38 PM | #3 |
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When I had to sketch level curves, my teacher showed me a nice and easy to understand method: Your equation is f(x,y) = x^2 + 2y^2 . Write it as z = x^2+2y^2 which could also be re-written as z=(x^2/1)+(y^2/1/2) Now that you have a clearer idea of what this could represent : if z=k a constant then for a certain z you have an ellipse of k=(x^2/1)+(y^2/1/2) Sketch it for some values and then connect the elements together. Since z can't be negative (x and y are both squared) it will be something like a parabola going up in the z-dir. So I guess it is a paraboloid, where each "slice" taken in z=k plane is an ellipse given by k=(x^2/1)+(y^2/1/2). |
| Mar30-10, 11:12 PM | #4 |
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sketching a level curve
thank you for your attention :)
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