Recent content by Alex.malh

Ok, i think I'm beginning to understand. To say that there is a potential difference is only relevant to their system only. There is no "global" zero potential. All potentials are relative. Only the difference is know between the two poles, that way it is impossible to know the difference...

Thanks for the quick reply. I changed the drawing a bit. It will help with my understanding. According to the teacher Ic will be 0A. According to me Earth is not at 230V. As there is a potential difference and a very small resistance Ic will not be 0A. So, is the teacher correct? and can...

Homework Statement So i was in a course yesterday and the "teacher" told us the following (which i had a hard time believing/understanding) There is a load connected to a transformer. Applied potential difference is 230V. The load is malfunctioning and the insulation isn't working anymore. The...

Thanks for the quick reply! so i solved it to: Ra= 1826N Rb= 5102N What i still don't get though is why av is negative? I would expect the plate to have a downward acceleration with the same sign as gravity acc. But now i solved it by having an upward acceleration.

Homework Statement A plate is fixed to the ceiling by two wires and to the wall by a single wire. The wall wire is cut. Calculate the tension in the two remaining wires. mass = 800 kg g = 10m/s² Dimensions in sketch Homework EquationsThe Attempt at a Solution Equations: Ra*cos30 + Rb*cos30 =...

Ok, thanks! I made an error by summing the masses for EW1. Solution is 3.87m/s for the interested.

Homework Statement There is a wagon (W) on wheels with a vertical pole of 2m. (mass 20kg) On the top of that pole there is a rope pendulum with an attached mass (M) of 10kg and length 1m. The starting position is a pendulum angle of 60°. No friction taken into account. What is the speed of the...

Both methods are correct. The second method is just a graphical representation of the first. But as Qwertywerty said: you can't just add vectors.

Ah yes of course. Well, I've got it now. 7cm spring elongation :) Thx a lot!

Thanks for the quick reply. New equations: F - w*cos45 - R*cos45 = (m1+m2)*ah (m1+m2)*g + w*sin45 - R*sin45 = (m1+m2) *av w=0.2*R Now to solve this I'm still missing a relationship between ah and av. I've taken av = ah ( angle is 45°, if the block has moved 1m to the right, it will have moved...

Homework Statement There is a block of 1kg (m1) resting frictionless on another block of 5kg (m2). m1 is connected by a horizontal spring to m2. m2 is resting on an inclined plane of 45°. Between m2 and the plane there is friction. A force of 200N is applied on m2, pushing it upwards. F=200N...

Don't you mean N instead of Pa?

Yes, that is watt. [kg] x [m/s²] = [N] = m x a = F you can rewrite your equation as: 1/s x (kg x m/s²) x m =1/s x N x m =Nm/s =W

UTS = ultimate tensile strain and see my first post. Be sure to check what concrete quality you have and check google afterwards.

Hello, Can you tell me which units you use in your equation? Normally its: P [W] = Q [m³/s] x dP [N/m²] [W] = [Nm/s] Hloss is cannot be in watt. Or in m or in Pa. If its in watt it is probably recalculated from pressure or head loss to power.