Solving Homework: Speed of Mass on Wagon

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SUMMARY

The discussion focuses on calculating the speed of a mass attached to a pendulum on a wagon, specifically when the pendulum passes the vertical pole for the first time. The initial potential energy (EM0) of the pendulum mass (10kg) is calculated to be 50J using the formula Ep = m * g * h. The final equation set up for energy conservation is 50J = EM1 + EW1, where EM1 is the kinetic energy of the pendulum mass and EW1 is the kinetic energy of the wagon and pendulum combined. The final speed of the mass compared to the wagon is determined to be 3.87 m/s.

PREREQUISITES
  • Understanding of potential energy and kinetic energy equations (Ep = m * g * h, Ek = m * v² / 2)
  • Basic knowledge of conservation of energy principles
  • Familiarity with trigonometric functions, specifically cosine
  • Concept of linear momentum conservation
NEXT STEPS
  • Study the principles of conservation of energy in mechanical systems
  • Learn about the application of trigonometry in physics problems
  • Explore the concept of linear momentum and its conservation in collisions
  • Investigate the effects of friction on pendulum motion and energy calculations
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and tutors looking to enhance their understanding of energy conservation and pendulum dynamics.

Alex.malh
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Homework Statement


There is a wagon (W) on wheels with a vertical pole of 2m. (mass 20kg)
On the top of that pole there is a rope pendulum with an attached mass (M) of 10kg and length 1m.
The starting position is a pendulum angle of 60°.

No friction taken into account.
What is the speed of the mass compared to the wagon the first time it passes the pole?

Homework Equations


Ep= m * g * h
Ek= m*v²/2

The Attempt at a Solution


1.
EM0= 10kg * 10 m/s² * (1m *cos60) = 50J
EW0= 0
2.
EM1= 10kg*VM²/2
EW1= (10kg+20kg) *VW²/2

50J=EM1+EW1

And now i don't know how to continue.
 
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Alex.malh said:

Homework Statement


There is a wagon (W) on wheels with a vertical pole of 2m. (mass 20kg)
On the top of that pole there is a rope pendulum with an attached mass (M) of 10kg and length 1m.
The starting position is a pendulum angle of 60°.

No friction taken into account.
What is the speed of the mass compared to the wagon the first time it passes the pole?

Homework Equations


Ep= m * g * h
Ek= m*v²/2

The Attempt at a Solution


1.
EM0= 10kg * 10 m/s² * (1m *cos60) = 50J
EW0= 0
2.
EM1= 10kg*VM²/2
EW1= (10kg+20kg) *VW²/2

50J=EM1+EW1

And now i don't know how to continue.
Conservation of linear momentum?
 
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Likes   Reactions: Qwertywerty
Ok, thanks!
I made an error by summing the masses for EW1.
Solution is 3.87m/s for the interested.
 

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