I think I see what you were trying to write in the previous post now and that actually is correct, you just didn't put parenthesis in the right place (you should check out how to use LaTeX on this board so we don't misinterpret what you're typing like I just did up there)
Q_{1i}=Q_{1f}+Q_{2f}...
It is a voltage difference that makes a charge move in a circuit. That is what the battery provides.
So we made this circuit do the following:
1) We closed S1 to charge C1. I assume you used Q=CV to find the solution for the charge on C1.
2) We opened S1. Now our voltage source is C1 only...
You can't do this
This is an error with units.Think about it like this: that system eventually wants there to be no net force on the charge carriers. There will need to be an equilibrium reached.
That sounds good to me.
If you have Linux you might be interested in the following packages:
gspiceui
gnucap
gEDA
gwave
They can help you model circuits and read voltage drops and currents and see how a circuit will respond to certain inputs etc etc. They're the Linux attempt to create...
Their ω is no doubt equal, they're both going through the same amount of radians as the other in the same time.
The problem is with arc lengths though--which is equal to θr (make sure θ is in radians). The girl on the outside moves further in the same amount of time, so the ball is actually...
You're missing something important in this question which is the difference between angular velocity (rad/s) and linear velocity (m/s). You don't need to be using angular momentum/moment of inertia.
Using ω is right while the girls are holding the ball, but when it is let go when it hits the...
You can solve it with a variable in place in the starting position though, you don't need a numerical solution, just use r1 and r2 = r1 + 0.1
vaironl, try thinking about this with energy considerations. Note that "electric potential" and the "potential energy" are NOT the same thing.
A very...
How about this, I think I need to proofread my posts a little better, I actually might have made a mistake in that one :redface:
Do you agree that, for a projectile launched at an angle theta, you can decompose an initial velocity as such:
v_{0x}=v_0cos(\theta)
v_{0y}=v_0sin(\theta)...
I think your method was indirectly solving for k hidden inside of that constant you chose.
You can multiply the new mass into the equation
\omega_1=\sqrt{\frac{k}{m_1}}
to get
\omega_1 \sqrt{m_2}=\sqrt{k\frac{m_2}{m_1}}
and you can subsitute in the solution for m2 from the equation...
Intro physics questions are easy mathematically, it is the concept that is difficult, as well as the visualization of the problem. So your professor is pretty correct imho.
I would look up those things I recommended as that is the main way I think it could be done relatively easily without...