Recent content by AMan24

Homework Statement [/B] Which is more stable cyclobutane or cycloheptane? Homework Equations [/B] [(n-2)180)]/n = angle The Attempt at a Solution [/B] So the closer the angle is to 109.5 the more stable (except for cyclopentane vs cyclohexane). n = number of carbons [(7-2)180)]/7 = 128.57...

I placed a hot metal lid on a cool surface. When i tried to pull it up, it had a lot of resistance, i had to really try to pull it up. I could hear sounds under the lid, I'm guessing it was boiling water. What do you think could have caused this resistance?

Homework Statement I'm not understanding the difference between them, this is for Uniform Circular Motion. Homework Equations ar = -ac = -v2/r The Attempt at a Solution So what i know is radial acceleration goes in a direction towards the radius (perpendicular to velocity), and tangential...

no there are no restrictions, so that must mean it does work, or actually, you said x = 3y. I am not sure... there's no restrictions I am aware of

Homework Statement sin2x + cos2x = 1 but would sin23x + cos23x = 1?Homework Equations none. The Attempt at a Solution [/B] I'm pretty sure sin23x + cos23x can't equal 1 otherwise the identity would probably be written as sin2cx + cos2cx = 1 and I've never seen it written like this. I was...

Homework Statement Homework Equations The Attempt at a Solution Here is my answer, i get 1/24 For my first step i divided both terms under the radical by 4, then split 1/4 into (1/2)2, i saw something very similar in my book so i did the same thing, but i just realized this has to be...

Homework Statement So LG is on 2° position, and you have a hydride shift. So you form one product on 2° and one product on 3°. Which product will be major which will be minor? Homework Equations none. The Attempt at a Solution I know hydride shift will be more major than a methide shift...

I learned in the earlier chapters that peaks and valleys of a fxn have points where f'=0 (i marked them with red x). A few chapters later it said if a fxn has 2 roots, then f'=0 (still the 1st graph). So does that mean if the graph of a fxn is like the 2nd graph, the peaks and valleys are not...

more resonance = longer bond

I just had a lab, and the results really aren't adding up to what i expected. And this is specifically about simple distillation, not fractional distillation. Lets say i have a solution of two liquids, one's boiling point is 90°C and the other is 110°C, a 20°C difference which is pretty close...

I think i might have figured it out. So for ketones and aldehydes, its just CO. For carboxylic acids and esters its CO2. For amides its CON.. and so on

Isn't that was ketone is? A CO and a CH3 = C2H3O

Homework Statement Lets say i have C5H10O.. The IHD is (5x2+2-10)/2 = 1 IHD So now i use my IR chart and i determine i have ketone Now i want to find the new IHD and also figure out what other atoms i have left. So i need to subtract C5H10O by ketone and figure out the new IHD. Homework...

I'm not sure, i got it from the website. I'm assuming its the plate but i have no idea. And yeah the temperature would be different depending on the amount of what I am heating, but I'm asking this for smaller amount substances, i should have specified that.

In my labs we use hot plates with a 0-10 temperature knob. The hot plates don't have a temperature monitor, so i have no idea how hot each number can increase it or how hot it is at the time. Sometimes i have labs where i have to heat something to more specific temperatures or else the reaction...