Recent content by Callisto

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    Process Physics: Exploring Information Theoretic Models

    Hi all, I was wondering what some of you thought about 'Information Theoretic Process Physics'? The topic seems fascinating, however somewhat difficult to come to grips with. I attached a link for those who might be interested. There have been papers published which are surly worth a...
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    Emissivity of a flat surface varies with zenith angle

    If the emissivity of a flat surface varies with zenith angle according to e=E*cos(theta) where E is the emissivity at zenith. Would this surface radiate isotropically? I think that because the emissivity varies then the emitted radiation varies accordingly so the energy measured from...
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    Emissivity e varies with zenith angle according to e = E*cos(theta)

    If the emissivity e varies with zenith angle according to e = E*cos(theta) where E is the emissivity normal to the surface. Would this surface be an isotropic source of radiation? Well, since e varies with angle then the flux density must vary accordingly so the surface would radiate...
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    How Can I Succeed in My Undergraduate Calculus of Variations Class?

    I see that we get L = int:dtheta*sqrt((dr/dtheta)^2+r^2) which is the length of the polar curve r=f(theta) how do i decide what is a worthy substitution for dtheta?
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    How Can I Succeed in My Undergraduate Calculus of Variations Class?

    Hi all, I seeking some advice about the calculus of variations. I am an undergraduate and i am enrolled in a topic of the above mentioned. After successfully completing the requirments for the topic, 3 weeks after commencement i am feeling way out of my depth. I understand that the calculus...
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    Taylor expansion

    Cheers James R!
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    Taylor expansion

    Taylor series for 1/(1-x) = (1-x)^-1 = 1 + x^2 + x^3 + x^4 +...= SUMi x^i Then sub in exp(-1) for x That's it?
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    Taylor expansion

    Hi How do you expand (1-exp(-1))^-1 as Taylor series Callisto
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    Lagrange multiplier problem

    thanks for your replies' from 0 = 2*lambda*x+ 4*rho*x = 2*x(lambda +2*rho) = 0 when x = 0 if x = 0 then y^2 = z^2 so z = y = +/-sqrt(15) so the min value is -sqrt(15), that must mean the max value is sqrt(15) is this right?
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    Lagrange multiplier problem

    This problem was given in my calc class during the semester, "Find the lowest point on the intersection of the sphere x^2+y^2 +z^2 = 30 and the cone 2*x^2 +y^2 = c^2". I don't know how to solve this problem with lagrange multipliers. How is it done? Thanks! Callisto
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    Calculating Minimum Distance p+q

    Thanks 2f must be minimum since if the object p is at infinity then 1/p=0 so q = f for an object at infinity.
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    Calculating Minimum Distance p+q

    1/0+1/0=1/0, 1/0 doesn't = 1/f is this why 0's are excluded?
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    Calculating Minimum Distance p+q

    1/0+1/0=0 , 0 doesn't = 1/f therefore 0's are excluded from the problem, correct? Callisto
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    Calculating Minimum Distance p+q

    solving 1/p+1/p=1/f for p i get -qf/(f-q) now i substitute this into p+q, then i get -q^2/(f-q). now if i use calculus to find the minimum value i differentiate -q^2/(f-q) and let it equal zero so d/dq= -q(2f-q)/(f-q)^2 =0 when q = 0 or 2f Repeating this process for p then p = 0 or...
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    Calculating Minimum Distance p+q

    Hi Peaple :!) How do you determine the minimum distance p+q between the object and image for given focal length given 1/p + 1/q = 1/f this may seem trivial, but i can't figure it out. any tips please Callisto
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