Recent content by Cate

Homework Statement A basketball player throws the ball at a 48° angle above the horizontal to a hoop whose centre is located a horizontal distance L = 4.30 m from the point of release and at a height h = 0.50 m above it. What initial speed is required if the basketball is to reach the centre...

The motion diagram below shows the position of a seat on a Ferris wheel at 12 moments. One full rotation is shown; the positions at moments 0 and 6 are labelled. For each of the following questions, choose the appropriate direction from the second diagram...

i'm sorry guys I'm really sleep deprived thanks

-5.86

I did it agai and got 5.71 which is still wrong...

Wait I plugged in four or t and got 27.84 for theta which I then plgged into my x= r. cos (theta) formula and got 8.36 m which is not the right answer...

Thanks for your help! but how do I find theta?

Homework Statement The circular motion of a particle in the x-y plane is given by the equations: r(t)= 6.46 m, theta (t)= (6.96 rad/s) t, where r is the distance from the origin and theta is the polar angle measured counterclockwise from the positve x-axis. Calculate the x-coordinate of the...

could someone please explain to me how to actor 11 degrees n question #2? Thanks

o.k i solved 1. 2(pi)/ (20995200) # of seconds in 243 days. I'm still stuck on ow to go about solving for 2.

Hi all, my homework question is this: 1. What is the angular speed in rad/s of a point on the equator of venus? (Rotation period: 243 days) 2. What is the angular speed in rad/s of a point on the surface of venus at latitude 11 degress south? I know this isn't that difficult but I can't...

I don't really understand what you mean, so Newton's second law ( F= Ma) In the place of P (for part a))Iinput FV then in the place of F I input Ma so it looks like V= (2ma(t)/m)^ (1/2) so the m's cancel out right? then what do I do?

Homework Statement An automobile with mass m accelerates starting from rest, while the engine supplies constant power P. a) Show that the speed is given as a function of time by v= (2Pt/m)^(1/2) b) Show that the acceleration is given as a function of time by a= (P/2mt)^(1/2) c)...

tangent line gets steeper?

Thanks guys, what about the seond half of the question? explain why your answer makes sense with the shape of the graph in mind.