Differentiaitng Problem (dy/dx)

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The discussion focuses on evaluating the rate of change of the y-component of a particle moving along the curve defined by the function y = x^2 + 2x, with a constant x-component change of 1 cm/sec. Participants calculate dy/dt using the derivative dy/dx = 2x + 2 and apply the chain rule to find specific values for x = -3, -2, -1, and 1. There is a consensus that as x increases, the slope of the tangent line becomes steeper, indicating that the rate of change of y with respect to time also increases. The relationship between the steepness of the graph and the rate of change is emphasized, illustrating how the graph's shape affects the particle's motion. Understanding these concepts is crucial for accurately interpreting the behavior of the particle along the curve.
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Homework Statement


Questions: Imagine a particle along the graph of the function y=x^2+2X. The X-component of the particle changes at a constant rate of 1cm /sec. First, evalute how fast the y-component of the particle is changing at the various points below. Then for each, explain why your answer makes sense with the shape of the graph in mind.

This is what I did:

Know:

dx/dt= 1

x= -3,-2,-1,1


Find:

dy/dt= ?


y=2X+2 dy/dt= 2(-3)+2 dx/dt =-4

and so on for all four values of x am I right?


Thanks!
 
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Um. I think so. y=x^2+2x. dy/dt=2x*dx/dt+2*dx/dt. Your notation is a little ambiguous.
 
Cate said:

Homework Statement


Questions: Imagine a particle along the graph of the function y=x^2+2X. The X-component of the particle changes at a constant rate of 1cm /sec. First, evalute how fast the y-component of the particle is changing at the various points below. Then for each, explain why your answer makes sense with the shape of the graph in mind.

This is what I did:

Know:

dx/dt= 1

x= -3,-2,-1,1


Find:

dy/dt= ?


y=2X+2 dy/dt= 2(-3)+2 dx/dt =-4
You mean dy/dx= 2x+ 2 and then dy/dt= -4.

and so on for all four values of x am I right?


Thanks!
 
Thanks guys, what about the seond half of the question? explain why your answer makes sense with the shape of the graph in mind.
 
Remember that the derivative is the slope of the tangent line. What happens to the tangent line to the graph as x gets larger?
 
tangent line gets steeper?
 
Yes, and so how fast does y change compared with x?
 
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