A basketball player throws the ball at a 48° angle above the horizontal to a hoop whose centre is located a horizontal distance L = 4.30 m from the point of release and at a height h = 0.50 m above it. What initial speed is required if the basketball is to reach the centre of the hoop? (Ignore the size of the ball.)
I've tried using two equations:
1.Vo= square root* gh/2sintheta
2. R= Vo^2Sin2theta/g
The Attempt at a Solution
Using the second formula I isolated or Vo and got 6.51 m/s but that wasn't the right answer also, that formula doesn't take into account the height while the first formula doesn't take into account the range...I know this isn't that dificult but if someone could point me in the right direction it would be appreciated!